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ratelena [41]
3 years ago
10

Solve the system of equations using the substitution method. x - 2y = -2 -4x + 3y = -5

Mathematics
2 answers:
umka21 [38]3 years ago
5 0

Answer:

x=16/5, y=13/5

Step-by-step explanation:

  1. Multiply by 4 on the first equation and get a new equation: 4x-8y=-8
  2. Plus the new and second equation: 4x-8y+(-4x+3y)=-8+(-5), and got -5y=-13, so y=13/5
  3. After getting y=13/5, substitute in the first equation, x-2*(13/5)=-5, and got x=16/5
djverab [1.8K]3 years ago
3 0
So do we solve both of them, or just one of them I’m confused.
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X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4
AfilCa [17]
Given a solution y_1(x)=x^4, we can attempt to find another via reduction of order of the form y_2(x)=x^4v(x). This has derivatives

{y_2}'=4x^3v+x^4v'
{y_2}''=12x^2v+8x^3v'+x^4v''

Substituting into the ODE yields

x^2(x^4v''+8x^3v'+12x^2v)-7x(x^4v'+4x^3v)+16x^4v=0
x^6v''+(8x^5-7x^5)v'+(12x^4-28x^4+16x^4)v=0
x^6v''+x^5v'=0

Now letting u(x)=v'(x), so that u'(x)=v''(x), you end up with the ODE linear in u

x^6u'+x^5u=0

Assuming x\neq0 (which is reasonable, since x=0 is a singular point), you can divide through by x^5 and end up with

xu'+u=(xu)'=0

and integrating both sides with respect to x gives

xu=C_1\implies u=\dfrac{C_1}x

Back-substitute to solve for v:

v'=\dfrac{C_1}x\implies v=C_1\ln|x|+C_2

and again to solve for y:

y=x^4v\implies \dfrac y{x^4}=C_1\ln|x|+C_2
\implies y=C_1\underbrace{x^4\ln|x|}_{y_2}+C_2\underbrace{x^4}_{y_1}

Alternatively, you can solve this ODE from scratch by employing the Euler substitution (which works because this equation is of the Cauchy-Euler type), t=\ln x. You'll arrive at the same solution, but it doesn't hurt to know there's more than one way to solve this.
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4 years ago
Graph the solution of liner equality 3y-2x less then or equal to 12
Svetradugi [14.3K]

Given the inequality;

3y-2x\leq12

Let's convert it to slope intercept form;

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So, the slope of the line is 2/3 which is positive, and the intercept on the y axis is 4.

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1 year ago
What's the answer to this math problem?
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Answer:

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Step-by-step explanation:

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