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ratelena [41]
2 years ago
10

Solve the system of equations using the substitution method. x - 2y = -2 -4x + 3y = -5

Mathematics
2 answers:
umka21 [38]2 years ago
5 0

Answer:

x=16/5, y=13/5

Step-by-step explanation:

  1. Multiply by 4 on the first equation and get a new equation: 4x-8y=-8
  2. Plus the new and second equation: 4x-8y+(-4x+3y)=-8+(-5), and got -5y=-13, so y=13/5
  3. After getting y=13/5, substitute in the first equation, x-2*(13/5)=-5, and got x=16/5
djverab [1.8K]2 years ago
3 0
So do we solve both of them, or just one of them I’m confused.
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URGENT PLS HELP MAX POINTS
bija089 [108]

Answer:

-103

243

Step-by-step explanation:

(q•r)(5) = q(r(5))

r(5) = 2(5²) + 1 = 51

q(51) = -2(51) - 1 = -103

(r•q)(5) = r(q(5))

q(5) = -2(5) - 1 = -11

r(-11) = 2(-11)² + 1 = 243

6 0
3 years ago
Which situation can be represented by the expression 5−8
Iteru [2.4K]

Answer:

The answer is C.)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Plss show the work<br> –4z + 8 = –2z
IceJOKER [234]

Answer:

z=-4/3

Step-by-step explanation:

8=-6z

z=-8/6

z=-4/3

4 0
2 years ago
Simplify (a+b)^3 + (a-b)^3 + 6a(a^2-b^2)
11111nata11111 [884]

Answer:

8a^3.

Step-by-step explanation:

(a+b)^3=a^3+b^3+3a^2b+3ab^2

(a-b)^3=a^3-b^3-3a^2b+3ab^2

(a+b)^3+(a-b)^3=2a^3+6ab^2

According to the question

(a+b)^3+(a-b)^3+6a(a^2-b^2)

Put in the value

=2a^3+6ab^2 +6a^3–6ab^2

=8a^3

7 0
3 years ago
Find Arc Measures of two diameters
svetoff [14.1K]

Answer:

m arc ACD =310

m arc AC = 130

Step-by-step explanation:

drawing the figure helps

if you do,  should get something like the figure below

filling in arc ad as 50 degrees tells you that the angle describing it is also 50 degrees; it's a central angle.

and we  know that 1/2 of a circle  is 180 degrees. so if you subtract 50 from 180 you'll get  130 which will be your measurement for arc AC (because it is a central angle and AC

+AD completes the 180 half.).

as well as that to get ACD, well 1st we know that arc AC is within arc ACD. that would mean that ACD has to be more than 130.

what you can do is subtract  50 from 360. the entire circle is 360, but  seeing as the arc is ACD (The rest of the circle excluding arc AD since we aren't looking for that measurement) we can just subtract.

subtracting 50 from 360 will give you 310

3 0
3 years ago
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