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scoundrel [369]

2 years ago

12

Before you factor you should check what two things?

2 answers:

Sergeeva-Olga [200]2 years ago

7 0

You can check your factoring by multiplying them all out to see if you get the original expression. If you do, your factoring is correct; otherwise, you might want to try again

gavmur [86]2 years ago

7 0

Answer:

I put all the steps to factoring, hopefully this helps! ^^

Step-by-step explanation:

-Check for common factors. If the terms have common factors, then factor out the greatest common factor (GCF) and look at the resulting polynomial factors to factor further.

-Determine the number of terms in the polynomial.

-Look for factors that can be factored further.

-Check by multiplying.

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Step-by-step explanation:

6 0

3 years ago

What is the equation of this line? y=12x−3 y=−12x−3 y=−2x−3 y=2x−3 Number graph ranging from negative 5 to 5 on both the x and y

Tems11 [23]

We are given that

A line passes through two points as

(0,-3) and (4,-1)

$(x_1,y_1)=(0,-3)$

$x_1=0,y_1=-3$

$(x_2,y_2)=(4,-1)$

$x_2=4,y_2=-1$

Firstly, we can find slope

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{-1+3}{4-0}$

$m=\frac{2}{4}$

$m=\frac{1}{2}$

now, we can use point slope form of line

$y-y_1=m(x-x_1)$

we can plug values

$y+3=\frac{1}{2} (x-0)$

$y+3=\frac{1}{2}x$

$y=\frac{1}{2}x-3$

so, the equation of line is

$y=\frac{1}{2}x-3$ ...............Answer

5 0

3 years ago

Read 2 more answers

If the initial point of a vector is (6, −5) and the terminal point is (2, −3), find the components of the vector. A) <−4, −8&

MissTica

Answer:

i honestly dont know this but im guessing its about 12th grade work.

4 0

3 years ago

It must exceed seven

nignag [31]

The digits that are between numbers 1 and 10 and larger than 7 are: 8, 9, 10

6 0

2 years ago

Solve the inequality |x| < 5. {x|-5 < x < 5} {x|x < -5 ∪ x > 5} {x|x -5 ∪ x < 5}

sesenic [268]

ANSWER

The correct answer is A

{ $x|-5$ }

<u>EXPLANATION</u>

$|x|$

This implies that

$x$

We solve the compound inequality to obtain,

$x-5$

Remember that, dividing through by negative 1 reverses the inequality sign

The solution set is

{ $x|-5$ }

8 0

3 years ago