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3 years ago

7

Each patron pays an annual fee of $36 to the library at the library collects $20,304 for an annual fee how many patrons are ther

e

1 answer:

IrinaK [193]3 years ago

5 0

Cuuck
in ur mom anwser 2692

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There is a gap of 1 metre you put a table into gap.The table is 70 centimetres wide.How much space is left?

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The price received for a bicycle is given by the equation b = 100 – 10x2, where x is the number of bicycles produced, in million

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II. 1.3

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Step-by-step explanation:

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Determine the slope and y-intercept of the line: y=-4x

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Equation y=-4x
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3 years ago

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

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3 years ago

The width of a rectangle is 4 less than half the length. If L represents the length, what equation can be use to find the width,

strojnjashka [21]

Answer:

W = 1/2L - 4

Step-by-step explanation:

The width is 4 less than 1/2 of the length.

w = 1/2L - 4

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