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monitta
3 years ago
6

What are the solution of the equation x^2- 4x -32 = 0 ?show your work and justify each step.

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
6 0
X^2-4x-32=0

(x+a)(x+b)

x^2-(a+b)x+ab

a+b=4
ab=-32

a=-b+4
(-b+4)b=-32

-b^2+4b=-32
b^2-4b-32=0
b=8,-4

If b=8, a=-4
If b=-4, a= 8

Plug in a and b to (x+a)(x+b)
x= -4, 8
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Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex
I am Lyosha [343]

Answer:

z = -1.53 --- test statistic

p = 0.1260 --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

n_1 = 80     \bar x_1= 104   \sigma_1 = 8.4

n_2 = 70    \bar x_2 = 106    \sigma_2 = 7.6

H_o: \mu_1 - \mu_2 = 0 --- Null hypothesis

H_a: \mu_1 - \mu_2 \ne 0 ---- Alternate hypothesis

\alpha = 0.05

Solving (a): The test statistic

This is calculated as:

z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}

So, we have:

z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}

z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}

z = \frac{-2}{\sqrt{0.8820 + 0.8251}}

z = \frac{-2}{\sqrt{1.7071}}

z = \frac{-2}{1.3066}

z = -1.53

Solving (b): The p value

This is calculated as:

p = 2 * P(Z < z)

So, we have:

p = 2 * P(Z < -1.53)

Look up the z probability in the z score table. So, the expression becomes

p = 2 * 0.0630

p = 0.1260

Solving (c): With \alpha = 0.05, what is the conclusion based on the p value

We have:

\alpha = 0.05

In (b), we have:

p = 0.1260

By comparison:

p > \alpha

i.e.

0.1260 > 0.05

So, we fail to reject the null hypothesis.

4 0
3 years ago
A car service chain hopes to increase productivity and has set a goal of an average of at least 25 customers served per day acro
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Answer:

Step-by-step explanation:

Given that:

population mean = 25

sample size = 50

sample mean = 24.02

standard deviation = 4.75

The null and alternative hypothesis can be computed as follows:

Null hypothesis:

\mathbf{H_o : \mu \geq 25}

Alternative hypothesis:

\mathbf{H_1 : \mu < 25}

b. Yes, the necessary assumptions to perform the inference are satisfied because the sample size is large and as a result, the data approximately follows a normal distribution.

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t = \dfrac{24.02 -25}{\dfrac{4.75}{\sqrt{50}}}

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The p -value =  P(T < -1.458)

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d. The p-value is the probability of finding the observed value when null hypothesis is true.

e.

Decision rule: To reject the null hypothesis if the level of significance at 0.05 is greater than the p-value.

Conclusion: We fail to reject the null hypothesis because the p-value is greater than the level of significance, hence, there is no sufficient evidence to conclude that the company has failed to meet its goal.

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Answer:

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x/44=75/100 can be used to solve a percent problem

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