Answer:
Given:
length of the wire = 0.20 meters
magnetic field strength = 0.45 newtons/amperes meter
speed = 10.0 meters per second
emf = B * l * v
B = flux density ; l = length of the wire ; v = velocity of the conductor
emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds
emf = 0.90 volts
The emf produced is 0.90 volts.
Step-by-step explanation:
Answer:
answer is:
Step-by-step explanation:
we are asked to find which system of equations can we use to find the roots of the equation:
since the system of equation in last part is given as:
so, on equating both the equations i.e. on equating both the values of 'y' we get the desired equation as:
.
Expand the square: 4(x-11)^ =25
4(x-11)(x-11)=25
Distribute : 4(x-11)(x-11)=25
4(x(x-11)-11(x-11))=25
Distribute: 4(x(x-11)-11(x-11))=25
4(x^-11x-11(x-11))=25
Solution: x=17/2
x=27/2
hope that helps
