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lilavasa [31]
3 years ago
15

The amount of time it takes for a student to complete a statistics quiz seems to have a uniform distribution with a minimum time

of 18 minutes and the maximum of 50 minutes. The professor wants to reward(with bonus marks) students who are in the lowest quarter of completion times. What completion time should be used for the cutoff for awarding bonus marks?
Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0
Q1 = 18 + 1/4(50 - 18) = 18 + 1/4(32) = 18 + 8 = 26

Therefore, the cutoff should be 26.
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An athlete was having her blood pressure monitored during a workout. The doctor found that the periodic function, P= 20 sin (8pi
lesya692 [45]

Answer:

(a) 110 mm Hg

(b) 70 mm Hg

(c) 3/4 second

(d) see the attachment

Step-by-step explanation:

(a) The sine function has a maximum value of +1, so the maximum value of p is ...

pmax = 20·(+1) +90 = 20+90 = 110 . . . . . mm Hg

__

(b) The sine function has a minimum value of -1, so the minimum value of p is ...

pmin = 20·(-1) +90 = -20+90 = 70 . . . . . mm Hg

__

(c) The period of the sine function is 2π, so the value of t that makes the argument be 2π will be the period.

8π/3·t = 2π

t = 2π·3/(8π) = 3/4 . . . . . . multiply by the inverse of the coefficient of t

The period of her heartbeat cycle is 3/4 seconds.

__

(d) a graph is attached.

4 0
3 years ago
The manager of a grocery store wants to determine the average amount of money spent at his store as it compares to the average d
dexar [7]

Given

Expenditures at Manager's Store; expenditures at Competitor's Store.

Find

a) average spent at each store

b) which store is better represented by the mean value

c) an explanation for the answer in ≥ 2 sentences

Solution

a) The sum of expenditures divided by the number of expenditures (15) is ...

... average for Manager's Store: $37.60

... average for Competitor's Store: $48.53

b) The expenditures at Manager's Store are well-represented by the mean (average).

c) The range of expenditures at Competitor's Store is significantly higher than at Manager's store, so a single number such as mean or median does not represent the data well. The expenditures at Manager's store are more compactly grouped around the mean and median, which are closer together, so the mean is a good representation of Manager's Store expenditures overall.

4 0
3 years ago
X*2/5=3/20 what si it nowwwwwwwwwwwwwwwwwwwww
gladu [14]

Answer: x = 11/20 = 0.550

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    x-2/5-(3/20)=0  

Step by step solution :

Step  1  :

            3

Simplify   ——

           20

Equation at the end of step  1  :

       2      3

 (x -  —) -  ——  = 0  

       5     20

Step  2  :

           2

Simplify   —

           5

Equation at the end of step  2  :

       2      3

 (x -  —) -  ——  = 0  

       5     20

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  5  as the denominator :

         x     x • 5

    x =  —  =  —————

         1       5  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x • 5 - (2)     5x - 2

———————————  =  ——————

     5            5    

Equation at the end of step  3  :

 (5x - 2)     3

 ———————— -  ——  = 0  

    5        20

Step  4  :

Calculating the Least Common Multiple :

4.1    Find the Least Common Multiple

     The left denominator is :       5  

     The right denominator is :       20  

       Number of times each prime factor

       appears in the factorization of:

Prime  

Factor   Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

5 1 1 1

2 0 2 2

Product of all  

Prime Factors  5 20 20

     Least Common Multiple:

     20  

Calculating Multipliers :

4.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 4

  Right_M = L.C.M / R_Deno = 1

Making Equivalent Fractions :

4.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      (5x-2) • 4

  ——————————————————  =   ——————————

        L.C.M                 20    

  R. Mult. • R. Num.       3

  ——————————————————  =   ——

        L.C.M             20

Adding fractions that have a common denominator :

4.4       Adding up the two equivalent fractions

(5x-2) • 4 - (3)     20x - 11

————————————————  =  ————————

       20               20    

Equation at the end of step  4  :

 20x - 11

 ————————  = 0  

    20    

Step  5  :

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 20x-11

 —————— • 20 = 0 • 20

   20  

Now, on the left hand side, the  20  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  20x-11  = 0

Solving a Single Variable Equation :

5.2      Solve  :    20x-11 = 0  

Add  11  to both sides of the equation :  

                     20x = 11

Divide both sides of the equation by 20:

                    x = 11/20 = 0.550

One solution was found :

                  x = 11/20 = 0.550

7 0
2 years ago
Tahmid has 96 G.I. Joe action figures and Sandeep has one-third as much as Tahmid does. How many figures must Tahmid give Sandee
Ann [662]
Tahmid has 96 figures, Sandeep has 1/3 of it so 
96(1/3) = 96/3 = 32
Sandeep has 32 figures

Tahmid 96 ; Sandeep 32

How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give. 
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each. 
6 0
3 years ago
10 people can paint a building in 5 days. if each person painted as quickly as the others then how much of the building could 7
Paul [167]
So basically it takes 10 people to paint a whole building. Forget about the 5 days. That's just there to confuse you. You have to first find out how much of a building can one person paint so, 1/10. So that means that 7 people can paint 7/10 of a building in 5 days
8 0
3 years ago
Read 2 more answers
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