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Tju [1.3M]
3 years ago
5

Evaluate the expression when x = –11. 2x – 19 a. 41 b. 3 c. –3 d. –41

Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0
2(-11)-19
-22-19
-41

D is the answer
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A 9.85 m ladder is placed against a wall. The height to the top of the ladder is 5 m more than the distance between the wall and
Dafna1 [17]

Given:

Length of the ladder = 9.85 m

The height to the top of the ladder is 5 m more than the distance between the wall and the foot of the ladder.

To find:

The height to the top and the distance between the wall and the foot of the ladder.​

Solution:

let x be the distance between the wall and the foot of the ladder. Then the height to the top of the ladder is (x+5).

Pythagoras theorem: In a right angle triangle,

Hypotenuse^2=Base^2+Perpendicular^2

In the given situation, hypotenuse is the length of ladder, i.e., 9.85 m. The base is x m and the height is (x+5) m.

Using the Pythagoras theorem, we get

(9.85)^2=x^2+(x+5)^2

97.0225=x^2+x^2+10x+25

0=2x^2+10x+25-97.0225

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Here, a=2, b=10,c=-72.0225. Using the quadratic formula, we get

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\dfrac{-10\pm \sqrt{(10)^2-4(2)(-72.0225)}}{2(2)}

x=\dfrac{-10\pm \sqrt{676.18}}{4}

Approximating the value, we get

x=\dfrac{-10\pm 26}{4}

x=\dfrac{-10+26}{4},\dfrac{-10-26}{4}

x=\dfrac{16}{4},\dfrac{-36}{4}

x=4,-9

Distance cannot be negative so x\neq -9.

Now we have x=4

x+5=4+5

x+5=9

Therefore, the base is 4 m and the height is 9 m.

5 0
3 years ago
Please help with this Geometry question. I just need help with the first question.
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Answer:

ST ≈ 5.21 cm

Step-by-step explanation:

ST = √(9² + 11²) - 9 = 5.212670403551895496...

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