5x/7 - 5 = 50 is 4. x = 77
The coordinates of the 2 given points are W(-5, 2), and X(5, -4).
First, we find the midpoint M using the midpoint formula:
Nex, we find the slope of the line containing M, perpendicular to WX. We know that if
m and
n are the slopes of 2 parallel lines, then
mn=-1.
The slope of WX is
.
Thus, the slope n of the perpendicular line is
.
The equation of the line with slope
containing the point M(0, -1) is given by:
Answer: 5x-3y-3=0
Answer:
a reflection over the x-axis and then a 90 degree clockwise rotation about the origin
Step-by-step explanation:
Lets suppose triangle JKL has the vertices on the points as follows:
J: (-1,0)
K: (0,0)
L: (0,1)
This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:
J: (0,1) , K: (0,0), L: (1,0)
Then we reflect it across the y-axis and get:
J: (0,1), K:(0,0), L: (-1,0)
Now we go through each answer and look for the one that ends up in the second quadrant;
If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.
If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.
If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.
The third answer is the only one that yields a transformation which leads back to the original position.
Answer:
0.
Step-by-step explanation:
Using the laws of logarithms:
log81/8 + 2log2/3 - 3log 3/2 + log 3/4
= log 81/8 + log (2/3)^2 - log (3/2)^3 + log 3/4
= log 81/8 + log 4/9 - log 27/8 + log 3/4
= log 81/8 + log 4/9 - (log 27/8 - log 3/4)
= log (81/8 * 4/9) - log (27/8 * 4/3)
= log 9/2 - log 9/2
= 0.
