All categories

2 years ago

The sum of 23 and a number is 39

Mathematics

2 answers:

Jobisdone [24]2 years ago

8 0

You add 23+39= and then you get 63. And that’s your answer

JulijaS [17]2 years ago

7 0

You will get 63! but someone already said it so they were right

You might be interested in

in class of 40 students report that english is their favorite class 40 percent of the students report that keyboard is there fav

olasank [31]

If 40% of students prefer keyboarding, 40/100*40=16 students like it best. If the remaining students prefer English, then 40-16=24 students like English best. Since 24 is more than 16, most students prefer English.

4 0

3 years ago

Need help with this ASAP: methods for solving right triangles.

sashaice [31]

Explanation:

1) sin(37º)=x/10.3————>trigonometric ratio (sine)

2)7²+10²=c²—————-> pythagorean theorem

3) using sine—————> sin(51º)=9/x

using tangent —————> tan(51º)=9/x and x = 7.3 (rounded)

4)using pythagorean theorem————> 6²+7²=c²

angle b is tanx=6/7 where x = 40.6 degrees, angle a is tanx=7/6 where x = 49.4

Answers:

1)x= 6.2

2)x= 12.2

3)x= 11.6 (rounded)

4)x= 9.2

credit to genan for question 3 and 4

ur welcome :)

correct me if im wrong

brainliest please?

4 0

1 year ago

Can someone please help me

Marat540 [252]

Answer:

992

Step-by-step explanation:

4 0

3 years ago

Find the midpoint of the line segment JK if j (4,6) and k(0,-4)

Snowcat [4.5K]

Answer:

$(2,1)$

General Formulas and Concepts:

Order of Operations: BPEMDAS

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define points

J (4, 6)

K (0, -4)

Step 2: Find midpoint

Substitute: $(\frac{4+0}{2},\frac{6-4}{2})$
Add/Subtract: $(\frac{4}{2},\frac{2}{2})$
Divide: $(2,1)$

4 0

3 years ago

What is the approximate area of a circle with a radius of 10 in?

yKpoI14uk [10]

$\huge\boxed{\textsf{A.}\ 78.5\ \text{in}^2}$

Correction to your question text: diameter, not radius.

The area of a circle is given by:

$A=\pi r^2$

The radius is half of the diameter.

$A=\pi\cdot\left(\dfrac{10}{2}\right)^2$

Substitute and solve.

$\begin{aligned}A&=\pi\cdot\left(\frac{10}{2}\right)^2\\&=\pi\cdot5^2\\&=\pi\cdot25\\&\approx\boxed{78.5}\end{aligned}$

5 0

1 year ago