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PolarNik [594]
3 years ago
13

Two classmates got together over the weekend to do their assigned History reading. Savannah can read 1 page per minute, while Li

am can read 3 pages per minute. When they met, Savannah had already read 62 pages, and Liam had already gotten through 2 pages. After a while, they both read the same number of pages. How many pages had each one read? How long did that take?
Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

The had read the books for 12 minutes.

Step-by-step explanation:

Let the number of minutes be x.

Tess = 51 + 1x

Ronald = 15 + 4x

When both read the same number of pages :

51 + 1x = 15 + 4x

3x = 36

x = 12

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Express in numbers six and three hundredths
Afina-wow [57]

Answer:

6.03

Step-by-step explanation:

'6' would be a whole number. When stating decimals, you would say the whole numbers before 'and'.

For example: 5.6 would be 'five and six tenths'. Note that five is before 'and'.

'Three hundredths' would be .03.

Therefore:

"Six and three hundredths" would be '6.03'.

4 0
3 years ago
What is 2/5 plus 3/15
Mandarinka [93]

Answer:9/15

Step-by-step explanation:

You change 2/5 to 6/15 by multiplying each by 3 then adding it to 3/15 to get 9/15.

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Determine the sample space of all of the possible outcomes of choosing a card numbered 1, 2, 3, or 4 and a blue, green, or yello
Alex17521 [72]

Answer:

Answer 2

Step-by-step explanation:

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3 years ago
If LO ≅LM and OP ≅ PM , then a correct conclusion would be:
Brrunno [24]

Answer:

Step-by-step explanation:

None of these Choices are correct..

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3 years ago
The article " Inconsistent Health Perceptions for US Women and Men with Diabetes" presents results of a survey of adults with di
musickatia [10]

Answer:

The 99% confidence level (-0.741, -0.659).

Step-by-step explanation:

The average body mass index (BMI) in a sample of 1559 men was 30.4, with a standard deviation of 0.6.

The average BMI in a sample of 1924 women was 31.1 with a standard deviation of 0.2.

Find a 99% confidence interval for the difference between the mean weights..

The formula for 99% Confidence Interval for difference between the mean weights =

μ is the population mean, and σ is the population standard deviation.

μ1 - μ2 ± z × √σ²1/n1 + σ²2/n2

The z score for 99% confidence interval = 2.576

30.4 - 31.1 ± 2.576 × √0.6²/1559 + 0.2²/1924

-0.7 ± 2.576 × √0.36/1559 + 0.04/1924

-0.7 ± 2.576 × √0.0002309173 + 0.00002079

-0.7 ± 2.576 ×√0.0002517073

-0.7 ± 2.576 × 0.015865286

-0.7 ± 0.04086897674

Hence, the 99% Confidence Interval is

-0.7 - 0.04086897674

= -0.74086897674

≈ -0.741

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=-0.65913102326

≈ -0.659

Therefore, the 99% confidence level (-0.741, -0.659).

5 0
2 years ago
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