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Korolek [52]
3 years ago
9

be The distance an object travels is determined by how fast it goes and for how long it moves. If an object's speed remains cons

tant, the formula is d= r., where d is the distance, ris the speed, and t is the time. a. If you drive at 50 miles per hour for 5 hours, how far will you have traveled? 200 miles b. 10 miles 250 miles d. 300 miles C. Please select the best answer ​
Mathematics
1 answer:
Colt1911 [192]3 years ago
7 0

Answer:

10 miles is answer because u should divide d=r

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Please answer both questions and show all your work. Thank you!!! :)
nignag [31]

(1) let "r" denote number of rabbits, "c"  number of chickens

Set up the equations:

r + c = 1000\\4r + 2c = 3150\\\\-2r -2c = -2000\\4r + 2c = 3150\\\\2r = 1150\implies r = 575\implies c = 425

Answer: There are 575 rabbits and 425 chickens

(2) m - number of Mike's stamps, a - number of Andrew's stamps.

Set up equations:

m = 4a\\m-8 = 2(a+8)\\\\4a-8=2a + 16\\2a = 24\implies a = 12\implies m = 48\\

Answer:  Mike has 48 stamps. Andrew has 12 stamps.

4 0
3 years ago
Read 2 more answers
Encuentra el valor de la incógnita -24/x = 6
Marat540 [252]

Answer:

x = -4

The solution is x = -4

3 0
3 years ago
There are 30 students in Mrs. Woodward’s class, and 1/5 of the class has their own cell phone. Of this group of students, 1/2 of
olga_2 [115]

Answer:

3 students

Step-by-step explanation:

There are 30 students in Mrs. Woodward’s class.

\dfrac{1}{5} of the class has their own cell phone, so

\dfrac{1}{5}\cdot 30=\dfrac{1}{5}\cdot \dfrac{30}{1}=6

students have their own cell phones.

\dfrac{1}{2} of those 6 students are allowed to use social media. So,

\dfrac{1}{2}\cdot 6=\dfrac{1}{2}\cdot \dfrac{6}{1}=3

students are allowed to use social media.

3 0
3 years ago
Me and my friend were checking answers, but then our answers differed on one question by one digit. The question is: [(21-13)+(3
Sunny_sXe [5.5K]

[(21-13)+(32-24)] x 4

[(8)+(8)] x 4

16 x 4

= 64

If this helped you, please list me as brainliest!

5 0
4 years ago
Read 2 more answers
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
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