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Ainat [17]
3 years ago
10

Point A is located at negative 5 over 8 and point B is located at negative 2 over 8 . What is the distance between points A and

B? (1 point)
negative 5 over 8 minus negative 2 over 8 = negative 3 over 8 ; therefore, the distance from A to B is absolute value of negative 3 over 8 equals 3 over 8 units

negative 5 over 8 minus negative 2 over 8 = negative 3 over 8 ; therefore, the distance from A to B is absolute value of negative 3 over 8 equals negative 3 over 8 units

negative 5 over 8 plus negative 2 over 8 = negative 7 over 8 ; therefore, the distance from A to B is absolute value of negative 7 over 8 equals 7 over 8 units

negative 5 over 8 plus negative 2 over 8 = negative 7 over 8 ; therefore, the distance from A to B is absolute value of negative 7 over 8 equals negative 7 over 8 units
Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0
The answer is A, hope it helps!
Dmitry [639]3 years ago
7 0
The answer is the first one, that it equals 3 over 8. Thanks!
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Repartir 310 nueces entre tres personas de modo que la segunda reciba 20 menos que la primera y 40 mas que la tercera
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2

Step-by-step explanation:

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3 0
2 years ago
The equation tan^2 x+1=sec^2 x is an identity true or false
Solnce55 [7]

Answer:

tan²x + 1 = sec²x is identity

Step-by-step explanation:

* Lets explain how to find this identity

∵ sin²x + cos²x = 1 ⇒ identity

- Divide both sides by cos²x

∵ sin x ÷ cos x = tan x

∴ sin²x ÷ cos²x = tan²x

- Lets find the second term

∵ cos²x ÷ cos²x = 1

- Remember that the inverse of cos x is sec x

∵ sec x = 1/cos x

∴ sec²x = 1/cos²x

- Lets write the equation

∴ tan²x + 1 = 1/cos²x

∵ 1/cos²x = sec²x

∴ than²x + 1 = sec²x

- So we use the first identity sin²x + cos²x = 1 to prove that

 tan²x + 1 = sec²x

∴ tan²x + 1 = sec²x is identity

8 0
3 years ago
Aya = a1 + (n - 1)d
Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

Step-by-step explanation:

Given

  • a₁ = -33
  • d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

substituting a₁ = -33 and d = 4 in the nth term of the sequence

a_n=-33+\left(n-1\right)4

\:a_n=-33+4n-4

a_n=4n-37

Thus, the nth term of the sequence is:

a_n=4n-37

now substituting n = 26 in the nth term to determine the 26th term of the sequence

a_n=4n-37

a_{26}=4\left(26\right)-37

a_{26}=104-37

a_{26}=67

Therefore, the 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

7 0
2 years ago
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swat32

Answer:

i would say A. The initial cost for renting a snowmobile is $75, with each hour of use costing an additional $25.

Step-by-step explanation:

5 0
3 years ago
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