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Ainat [17]
3 years ago
10

Point A is located at negative 5 over 8 and point B is located at negative 2 over 8 . What is the distance between points A and

B? (1 point)
negative 5 over 8 minus negative 2 over 8 = negative 3 over 8 ; therefore, the distance from A to B is absolute value of negative 3 over 8 equals 3 over 8 units

negative 5 over 8 minus negative 2 over 8 = negative 3 over 8 ; therefore, the distance from A to B is absolute value of negative 3 over 8 equals negative 3 over 8 units

negative 5 over 8 plus negative 2 over 8 = negative 7 over 8 ; therefore, the distance from A to B is absolute value of negative 7 over 8 equals 7 over 8 units

negative 5 over 8 plus negative 2 over 8 = negative 7 over 8 ; therefore, the distance from A to B is absolute value of negative 7 over 8 equals negative 7 over 8 units
Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0
The answer is A, hope it helps!
Dmitry [639]3 years ago
7 0
The answer is the first one, that it equals 3 over 8. Thanks!
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4x - 9 = 2x + 7

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Shauna is 10 inches shorter than Ryan, together their heights total 140 inches. How tall is each person?
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4 years ago
Which equation is the inverse of y = 9x2 - 4?
m_a_m_a [10]

Answer:

The inverse will be:

y' = \frac{\sqrt{x+4}}{3}

Step-by-step explanation:

In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :

f(x)  = 9x^{2} - 4

y = 9x^{2} - 4

x = 9y' ^{2} - 4

Now solve for y'.

First add 4 in both sides of the equation and change to the left y'.

x + 4= 9y'^{2} - 4+4

9y'^{2} = x + 4

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9y'^{2}/9 = (x + 4)/9

y'^{2} = (x + 4)/9

Now you will have to clear y, with the square root.

[tex]y'^{\frac{2}{2}} = \sqrt{x + 4}  / \sqrt{9}[/tex] =

Simplifying terms

y' = \frac{\sqrt{x+4}}{3}

f^{-1}(x)  = \frac{\sqrt{x+4}}{3}

You can check the answer by doing the evaluation of the following equation:

(f o f^{-1} ) (x)

substitute the equation for y' or inverse function f^{-1}

f(\frac{\sqrt{x+4} }{3})

Now substitue the value into f(x)

You will have

= 9(\frac{\sqrt{x+4} }{3}} )^{2}  - 4\\\\Solving\\\\9(\frac{{x+4} }{9}} )  - 4

=x

5 0
3 years ago
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