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Ainat [17]
3 years ago
10

Point A is located at negative 5 over 8 and point B is located at negative 2 over 8 . What is the distance between points A and

B? (1 point)
negative 5 over 8 minus negative 2 over 8 = negative 3 over 8 ; therefore, the distance from A to B is absolute value of negative 3 over 8 equals 3 over 8 units

negative 5 over 8 minus negative 2 over 8 = negative 3 over 8 ; therefore, the distance from A to B is absolute value of negative 3 over 8 equals negative 3 over 8 units

negative 5 over 8 plus negative 2 over 8 = negative 7 over 8 ; therefore, the distance from A to B is absolute value of negative 7 over 8 equals 7 over 8 units

negative 5 over 8 plus negative 2 over 8 = negative 7 over 8 ; therefore, the distance from A to B is absolute value of negative 7 over 8 equals negative 7 over 8 units
Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0
The answer is A, hope it helps!
Dmitry [639]3 years ago
7 0
The answer is the first one, that it equals 3 over 8. Thanks!
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I NEED HELP PLEASE HELP ME
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Answer:
294.14cm^2

Explanation:

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Then find the area of the two semicircles, semicircle + semicircle = 1 circle:

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(7^2)(3.14) = 153.86

Subtract the area of the two semicircles from the whole paper area:
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I hope this isn’t too confusing :)


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8 0
3 years ago
∠A and ​ ∠B ​ are vertical angles with m∠A=x and m∠B=3x−60 . What is m∠A ?
quester [9]
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Hope this helps!
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