Answer:
Perimeter = 60
Step-by-step explanation:
because l bisects AB:
3y+1 = 5y-5
reduce:
2y = 6
y = 3
and:
2x+4 = 4x-12
reduce:
2x = 16
x = 8
AB = (3y+1) + (5y-5)
AB = 8y-4
substitute for y
AB = 8(3)-4
AB = 20
Perimeter = (2x+4) + (4x-12) + 20
reduce:
perimeter = 6x+12
substitute for x:
Perimeter =6(8)+12
reduce:
Perimeter = 60
The zeros of the given functions are shown on the attached picture.
The first one is 17 13/15 the second one is 22 1/20
Answer:For these, n is equal to the term you want. So you substitute the number in for whichever term you want. This means:
a) 1 (1st term) + 5 = 6
2 (2nd term) + 5 = 7
3 (3rd term) + 5 = 8
4 (4th term) + 5 = 9
10 (10th term) + 5 = 15
And so on for b (not going to keep writing the term, I’m sure you get that by now.
b) 2(1) - 1 = (2x1) - 1 = 1
2(2) - 1 = (2x2) - 1 = 3
2(3) - 1 = (2x3) - 1 = 5
2(4) - 1 = (2x4) - 1 = 7
2(10) - 1 = (2x10) - 1 = 19
Hope this helps :)
