Xavier bought a shirt that was on sale for 20% off the original price. He also used a coupon that gave him an extra 15% off the
1 answer:
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Answer:
A) The researcher should reject the null hypothesis with a = .05 but not with a = .01.
Step-by-step explanation:
State the null and alternative hypotheses to be tested
On this case we can assume that the researcher conduct a one right tailed test hypothesis like on this way:
Null hypothesis:
Alternative hypothesis:
The statistic for this case is given by:
(1)
z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
On this case we have the value for z score given z =+1.85
It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.
The significance level provided . The next step would be calculate the p value for this test.
Since is a one right tail test the p value would be:
If we compare the p value obtained and the significance level given we can take a decision:
A) The researcher should reject the null hypothesis with a = .05 but not with a = .01.
YES, since the p value it's higher than the significance level of 0.01 so we FAIL to reject the null hypothesis at this significance level. And for the significance level 0.05 we have that and we can reject the null hypothesis.
B) The researcher should reject the null hypothesis with either a = .05 or a = .01.
No since the p value it's higher than the significance level of 0.01 so we FAIL to reject the null hypothesis at this significance level
C) The researcher should fail to reject H0 with either a = .05 or a = .01.
No, for the significance level of 0.05 we reject the null hypothesis since
D) This cannot be answered without additional information.
No, we have enough info to answer the question
1. 
2. -2+5n or 5n-2
3. (12s)+150 where s=number of students
4. 3(32)+1(53)=96+53=159 per hour, so 159h
9. √105 is irrational, -4 is an integer, 4/3 is a rational number, order is -4,3/4, √105
10. 3²=9, 4²=16, so between 3 and 4, but closer to 4, so √14≈4
11. that is the associative property, it deals with moving parentahees around
12. 2(6.25)+1(5.50)+2(2.75)=2(6.25+2.75)+1(5.50)=2(9)+5.5=18+5.5=23.5
13. yes, because they are both 2 less than 3 times of a number
14. maybe 18 times 3, so (4²+2) times 3=54
2. -2+5n or 5n-2
3. (12s)+150 where s=number of students
4. 3(32)+1(53)=96+53=159 per hour, so 159h
9. √105 is irrational, -4 is an integer, 4/3 is a rational number, order is -4,3/4, √105
10. 3²=9, 4²=16, so between 3 and 4, but closer to 4, so √14≈4
11. that is the associative property, it deals with moving parentahees around
12. 2(6.25)+1(5.50)+2(2.75)=2(6.25+2.75)+1(5.50)=2(9)+5.5=18+5.5=23.5
13. yes, because they are both 2 less than 3 times of a number
14. maybe 18 times 3, so (4²+2) times 3=54