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3 years ago

Write an expression that is equivalent to .........

Mathematics

1 answer:

Soloha48 [4]3 years ago

8 0

Answer:

Step-by-step explanation:

1/3x+2/3x-2/3x: x equasion

3/4+(-1/4)

1/3x + 2/4(or 1/2)

1/3x+1/2

(note that positive 2/3 and -2/3 cancel out)

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HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP(25 points)

miskamm [114]

Answer: I hope it helps :)

x=6 , y=6√3
x =23√3 , y=23
u =12 , v= 6
a =18√2 , b =18
x = 13 , y= 13

Step-by-step explanation:

$Hypotenuse =x\\Opposite =y \\Adjacent =6\\\alpha = 6\\Let's\: find\: the \:hypotenuse\: first\\Using SOHCAHTOA\\Cos \alpha = \frac{adj}{hyp} \\Cos 60 = \frac{6}{x} \\\frac{1}{2} =\frac{6}{x} \\Cross\:Multiply\\x = 12\\Let's\: find\: y\\Hyp^2=opp^2+adj^2\\12^2=y^2+6^2\\144=y^2+36\\144-36=y^2\\108=y^2\\\sqrt{108} =\sqrt{y^2} \\y=6\sqrt{3}$

$Opposite =x\\Hypotenuse = 46\\Adjacent =y \\\alpha =60\\Using \: SOHCAHTOA\\Sin \alpha =\frac{opp}{adj} \\Sin 60=\frac{x}{46}\\\\\frac{\sqrt{3} }{2} =\frac{x}{46} \\2x=46\sqrt{3} \\x = \frac{46\sqrt{3} }{2} \\x =23\sqrt{3} \\\\Hyp^2=opp^2+adj^2\\46^2=(23\sqrt{3} )^2+y^2\\2116=1587+y^2\\2116-1587=y^2\\529=y^2\\\sqrt{529} =\sqrt{y^2} \\y = 23$

$Hypotenuse = u\\Opposite =6\sqrt{3} \\Adjacent = v\\\alpha =60\\Sin\: 60 = \frac{6\sqrt{3} }{u} \\\frac{\sqrt{3} }{2} =\frac{6\sqrt{3} }{u} \\12\sqrt{3} =u\sqrt{3} \\\\\frac{12\sqrt{3} }{\sqrt{3} } =\frac{u\sqrt{3} }{\sqrt{3} } \\u = 12\\Hyp^2=opp^2+adj^2\\12^2= (6\sqrt{3} )^2+v^2\\144=108+v^2\\144-108=v^2\\36 = v^2\\\sqrt{36} =\sqrt{v^2} \\\\v =6$

$Hypotenuse = a\\Opposite =18 \\Adjacent = b\\\alpha =45\\Tan \alpha = opp/adj\\Tan \:45 =18/b\\1=\frac{18}{b}\\ b = 18\\\\Hyp^2=Opp^2+Adj^2\\a^2 = 18^2+18^2\\a^2=324+324\\a^2=648\\\sqrt{hyp^2} =\sqrt{648}\\ \\a =18\sqrt{2}$

$Hypotenuse = 13\sqrt{2}\\ Opposite =x\\Adjacent = y\\\alpha =45\\Sin\:\alpha = opp/hyp\\Sin 45=x/13\sqrt{2}\\ \\\frac{\sqrt{2} }{2} =\frac{x}{13\sqrt{2} } \\2x=26\\2x/2=26/2\\\\x = 13\\\\Hyp^2=opp^2+adj^2\\(13\sqrt{2})^2=13^2+y^2\\ 338=169+y^2\\338-169=y^2\\169=y^2\\\sqrt{169} =\sqrt{y^2} \\13 = y$

7 0

3 years ago

Ill give brainliest - please help ASAP<br><br> WITH THE WORK THO PLEASE?

evablogger [386]

Answer:

this is your answer look it once

5 0

3 years ago

Can you guys help me find the answer

alukav5142 [94]

6+2=8
:))))))))))))))

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3 years ago

Read 2 more answers

Determine the domain and range for each of the following:

LiRa [457]

Answer

Domain is the values x can be.

Range is the values y can be.

1st Graph)

D: -8 < x < 3

R: 3 < y < 9

2nd Graph)

D: -4<x<4

R: -4<y<4

3rd Graph)

-Note that this graph has an open and closed circle. Which means one is open and the other is closed on the interval. I will use brackets to make it easier.

D: [-4,3)

R: (-6,2)

6 0

3 years ago

Pls help I will give you 15 points

STALIN [3.7K]

Answer:

Ana still needs to read 1/5 of th journal

8 0

3 years ago