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3 years ago

Which of the following is a solution to the equation x^2 - 7x +5?

Mathematics

1 answer:

Dahasolnce [82]3 years ago

5 0

X^2-14+5 I’m not sure though

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Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5) to the plane x y z = 9.

zlopas [31]

One function you would be trying to minimize is
<span>f(x, y, z) = d² = (x - 4)² + y² + (z + 5)² </span>

<span>Your values for x, y, z, and λ would be correct, but </span>
<span>d² = (20/3 - 4)² + (8/3)² + (-7/3 + 5)² </span>
<span>d² = (8/3)² + (8/3)² + (8/3)² </span>
<span>d² = 64/3 </span>
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4 0

3 years ago

What are the coefficients in the expression 4x - 7y + 5 ?

3241004551 [841]

Answer:

4 and -7

Step-by-step explanation:

a coefficient is a number that is being multiplied with a variable (ex:5a) in this case the coefficients are 4 and -7

6 0

2 years ago

Read 2 more answers

What is 1/5 times 5/6 use a fraction modelto to help you solve.

lara [203]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

4 0

2 years ago

What is 48% written as a fraction? (in simplest form) A) 1 48 B) 6 25 C) 12 25 D) 24 25

alexgriva [62]

Answer:

48% is 12/25 as a fraction. So C

3 0

3 years ago

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

The probability that both televisions work is: 0.42

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

4 0

3 years ago