Hi okay i’m gonna write the explanation i hope you give me a brilliant if you think I’m deserving it thank you
(x-5)2=16
The first step you can take to solve this quadratic is to take the square root of both sides of the equation.
√[(x-5)2]=√(16)
When you take the square root of a term that is square it equals what is inside the parentheses.
So on the left side, you have x-5
On the right side, you are what we call "forcing" the square root. When this happens, you need to put ±. Why? Good question. When you square a negative number it positive; when you square a positive number it is also positive.
The √16 = ±4
So now we have;
x-5=±4
What do you do with that?
You make two separate equations.
x-5=4 and x-5=-4
x=9 x=1
Let's check our answers
x=9
(x-5)2=16
(9-5)2=16
42=16
16=16 it checks
x=1
(x-5)2=16
(1-5)2=16
(-4)2=16
16=16 it also checks
ANSWER: x=9 and x=1
2log10(2vx2) is the answer
Answer and Explanation:
Number of classes = 8
Highest value =2300
Lowest value = 1250
Class width= highest value – lowest value / number of classes
= 2300 – 1250/8
= 131.25 = 132
So, we can write class as 1250+132=1382
Class frequency
1250-1382 2
1382-1514 3
1514-1646 6
1646-1778 2
1778-1910 3
1910-2042 2
2042-2174 1
2174-2306 1
So we know that it must be between 9.5 9.7.. So it has to be 9.56763865854637984... (rounded 9.57) it is irrational because it has no pattern.
Answer:
C
Step-by-step explanation:
2ab * sqrt[3](192ab^2) - 5 * sqrt[3](81 a^4b^5) =
= 2ab * sqrt[3](4^3 * 3 * a * b^2) - 5 * sqrt[3](3^3 * 3 * a^3 * a * b^3 * b^2)
= 2ab * 4 sqrt[3](3 * a * b^2) - 5 * 3 * a * b * sqrt[3](3 * a * b^2)
= 8ab * sqrt[3](3 * a * b^2) - 15ab * sqrt[3](3 * a * b^2)
= -7ab * sqrt[3](3ab^2)
Answer: C
