Question

What is the area of a parallelogram if its length is x+4 and its height is x+3

Answer 1

Area of a parallelogram is:

$\sf A=bh$

Where 'b' is the base and 'h' is the height. Plug in what we know:

$\sf A=(x+4)(x+3)$

Distribute(multiply everything in the first parenthesis to everything in the second parenthesis):

$\sf x\times x=x^2$
$\sf x\times 3=3x$
$\sf 4\times x=4x$
$\sf 4\times 3=12$

So we have:

$\sf A=x^2+3x+4x+12$

Combine like terms(3x + 4x = 7x):

$\sf A=\boxed{\sf x^2+7x+12}$