Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
By substitution, we have that
and
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer: My bad if I butchered any answers. It was hard to read tbh
Step-by-step explanation:
D.) You can only factor out an x here. So you'd get: 
E.) You can factor out a 3x^2y to get: 
F.) You can factor out a 3xy to get: 
G.) You can factor out a -4ab to get: 
Answer:
(y - -2) (6 - 3) - (2 - -2) (x - 3) = 0
6y + 2 - 3y - 6 -2x +6 +2x +6 = 0
3y +8 =0
3y = -8
y = -8/3
Step-by-step explanation:
Answer:
24/25
Step-by-step explanation:
Step 1: Define systems of equation
10x - 16y = 12
5x - 3y = 4
Step 2: Rewrite one of the equations
5x = 4 + 3y
x = 4/5 + 3y/5
Step 3: Solve for <em>y</em> using Substitution
- Substitute 2nd rewritten equation into 1: 10(4/5 + 3y/5) - 16y = 12
- Distribute the 10 to both terms: 40/5 + 30y/5 - 16y = 12
- Simplify the fractions down: 8 + 6y - 16y = 12
- Combine like terms (y): 8 - 10y = 12
- Subtract 8 on both sides: -10y = 4
- Divide both sides by -10: y = 4/-10
- Simply the fraction down: y = -2/5
Step 4: Substitute <em>y</em> back into an original equation to solve for <em>x</em>
- Substitute: 5x - 3(-2/5) = 4
- Multiply: 5x + 6/5 = 4
- Subtract 6/5 on both sides: 5x = 14/5
- Divide both sides by 5: x = 14/25
Step 5: Check to see if solution set (14/25, -2/5) is a solution.
- Substitute into an original equation: 10(14/25) - 16(-2/5) = 12
- Multiply each term: 28/5 + 32/5 = 12
- Add: 12 = 12
Here, we see that x = 14/25, y = -2/5 and solution (14/25, -2/5) indeed works.
Step 6: Find <em>x</em> <em>- y</em>
x = 14/25
y = -2/5
- Substitute: 14/25 - (-2/5)
- Simplify (change signs): 14/25 + 2/5
- Add: 24/25
Hope this helped! :)
