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ozzi
2 years ago
6

How can I reflect this horizontally without a value for h?

Mathematics
1 answer:
Alex_Xolod [135]2 years ago
3 0

Answer:

Another transformation that can be applied to a function is a reflection over the x– or y-axis. A vertical reflection reflects a graph vertically across the x-axis, while a horizontal reflection reflects a graph horizontally across the y-axis. The reflections are shown in Figure 9.

Graph of the vertical and horizontal reflection of a function.

Figure 9. Vertical and horizontal reflections of a function.

Notice that the vertical reflection produces a new graph that is a mirror image of the base or original graph about the x-axis. The horizontal reflection produces a new graph that is a mirror image of the base or original graph about the y-axis.

A GENERAL NOTE: REFLECTIONS

Given a function \displaystyle f\left(x\right)f(x), a new function \displaystyle g\left(x\right)=-f\left(x\right)g(x)=−f(x) is a vertical reflection of the function \displaystyle f\left(x\right)f(x), sometimes called a reflection about (or over, or through) the x-axis.

Given a function \displaystyle f\left(x\right)f(x), a new function \displaystyle g\left(x\right)=f\left(-x\right)g(x)=f(−x) is a horizontal reflection of the function \displaystyle f\left(x\right)f(x), sometimes called a reflection about the y-axis.

HOW TO: GIVEN A FUNCTION, REFLECT THE GRAPH BOTH VERTICALLY AND HORIZONTALLY.

Multiply all outputs by –1 for a vertical reflection. The new graph is a reflection of the original graph about the x-axis.

Multiply all inputs by –1 for a horizontal reflection. The new graph is a reflection of the original graph about the y-axis.

EXAMPLE 7: REFLECTING A GRAPH HORIZONTALLY AND VERTICALLY

Reflect the graph of \displaystyle s\left(t\right)=\sqrt{t}s(t)=√

t

(a) vertically and (b) horizontally.

SOLUTION

a. Reflecting the graph vertically means that each output value will be reflected over the horizontal t-axis as shown in Figure 10.

Graph of the vertical reflection of the square root function.

Figure 10. Vertical reflection of the square root function

Because each output value is the opposite of the original output value, we can write

\displaystyle V\left(t\right)=-s\left(t\right)\text{ or }V\left(t\right)=-\sqrt{t}V(t)=−s(t) or V(t)=−√

t

Notice that this is an outside change, or vertical shift, that affects the output \displaystyle s\left(t\right)s(t) values, so the negative sign belongs outside of the function.

b.

Reflecting horizontally means that each input value will be reflected over the vertical axis as shown in Figure 11.

Graph of the horizontal reflection of the square root function.

Figure 11. Horizontal reflection of the square root function

Because each input value is the opposite of the original input value, we can write

\displaystyle H\left(t\right)=s\left(-t\right)\text{ or }H\left(t\right)=\sqrt{-t}H(t)=s(−t) or H(t)=√

−t

Notice that this is an inside change or horizontal change that affects the input values, so the negative sign is on the inside of the function.

Note that these transformations can affect the domain and range of the functions. While the original square root function has domain \displaystyle \left[0,\infty \right)[0,∞) and range \displaystyle \left[0,\infty \right)[0,∞), the vertical reflection gives the \displaystyle V\left(t\right)V(t) function the range \displaystyle \left(-\infty ,0\right](−∞,0] and the horizontal reflection gives the \displaystyle H\left(t\right)H(t) function the domain \displaystyle \left(-\infty ,0\right](−∞,0].

TRY IT 2

Reflect the graph of \displaystyle f\left(x\right)=|x - 1|f(x)=∣x−1∣ (a) vertically and (b) horizontally.

Solution

EXAMPLE 8: REFLECTING A TABULAR FUNCTION HORIZONTALLY AND VERTICALLY

A function \displaystyle f\left(x\right)f(x) is given. Create a table for the functions below.

\displaystyle g\left(x\right)=-f\left(x\right)g(x)=−f(x)

\displaystyle h\left(x\right)=f\left(-x\right)h(x)=f(−x)

\displaystyle xx 2 4 6 8

\displaystyle f\left(x\right)f(x) 1 3 7 11

SOLUTION

For \displaystyle g\left(x\right)g(x), the negative sign outside the function indicates a vertical reflection, so the x-values stay the same and each output value will be the opposite of the original output value.

\displaystyle xx 2 4 6 8

\displaystyle g\left(x\right)g(x) –1 –3 –7 –11

For \displaystyle h\left(x\right)h(x), the negative sign inside the function indicates a horizontal reflection, so each input value will be the opposite of the original input value and the \displaystyle h\left(x\right)h(x) values stay the same as the \displaystyle f\left(x\right)f(x) values.

\displaystyle xx −2 −4 −6 −8

\displaystyle h\left(x\right)h(x) 1 3 7 11

TRY IT 3

\displaystyle xx −2 0 2 4

\displaystyle f\left(x\right)f(x) 5 10 15 20

Using the function \displaystyle f\left(x\right)f(x) given in the table above, create a table for the functions below.

a. \displaystyle g\left(x\right)=-f\left(x\right)g(x)=−f(x)

b. \displaystyle h\left(x\right)=f\left(-x\right)h(x)=f(−x)

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Step-by-step explanation:

It's given in the question,

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m∠A + m∠B + m∠C = 180°

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By sine rule,

\frac{\text{sin}(\angle A)}{BC}=\frac{\text{sin}(\angle C)}{AB}

\frac{\text{sin}(60)}{BC}=\frac{\text{sin}(45)}{8}

BC = \frac{8\text{sin}(60)}{\text{sin}(45)}

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Answer:

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Step-by-step explanation:

To write the slope-intercept form equation for a line, you need to know the slope and the y-intercept. These can be found from their respective formulas.

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<h3>slope</h3>

The slope of a line between points (x1, y1) and (x2, y2) is given by the formula ...

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The y-intercept is the value of y where the line crosses the y-axis. That axis is where x = 0. There is a formula that can be used to find the y-intercept from the slope and a point on the line:

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2 years ago
What is 32986538537 plus 78.9 times 5
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Answer:

164,932,693,079.5

Step-by-step explanation:

To start you must add 78.9 to 32,986,538,537 which will give you 32,986,538,615.9. Then you must multiply 5.

9*5=45 keep the keep the 4 drop the 5

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4 years ago
Marty made a $220 bank deposit using $10 bills and $5 bills. She gave the teller a total of 38 bills, how many $5 bills were in
Luda [366]

ANSWER: 32 five-dollar bills

======

EXPLANATION:

Let x be number of $5 bills

Let y be number of $10 bills

Since we have total of 38 bills, we must have the sum of x and y be 38

x + y = 38 (I)

Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):

5x + 10y = 220 (II)

System of equations:

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ 5x + 10y &= 220 && \text{(II)} \end{aligned} \right.

Divide both sides of equation (II) by 5 so our numbers become smaller

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ x + 2y &= 44 && \text{(II)} \end{aligned} \right.

Rearrange (I) to solve for y so that we can substitute into (II)

\begin{aligned} x + y &= 38 && \text{(I)} \\ y &= 38 - x \end{aligned}

Substituting this into equation (II) for the y:

\begin{aligned} x + 2y &= 44 && \text{(II)} \\ x + 2(38 - x) &= 44\\ x + 76 - 2x &= 44 \\ -x &= -32 \\ x &= 32 \end{aligned}

We have 32 five-dollar bills

======

If we want to finish off the question, use y = 38 - x to figure out number of $10 bills

y = 38 - 32 = 6

32 five-dollar bills and 6 ten-dollar bills

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