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sashaice [31]
2 years ago
11

I need help??????????????

Mathematics
2 answers:
Likurg_2 [28]2 years ago
7 0

Answer:

20

Step-by-step explanation:

50*0.40=20

Stels [109]2 years ago
4 0

Answer:

20 times at first base

Step-by-step explanation:

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16% of all Americans live in poverty. If 41 Americans are randomly selected, find the probability that
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3 0
2 years ago
The first day of Sam's vacation was a Monday. What day of the week was the Day 36 of Sam's vacation?
makvit [3.9K]

Answer:

A. Monday

Step-by-step explanation:

The solution to this problem can be found by creating a table

If Day 1 was Monday, then

Mon    Tues      Wed      Thur    Fri      Sat      Sun

1              2           3             4        5        6          7

8             9           10           11        12       13        14

...............

We can see that the multiples of 7 are falling on Sundays so we will divide 36 by 7 to get the closest multiple of 7 to 36.

The closest multiple of 7 near 36 is 35 so Day 35th will fall on Sunday and Day 36 will be on Monday

Hence, Option A is the correct answer..

3 0
3 years ago
Several children are standing in line to ride a roller coaster. Their heights, in inches, are 59, 68, 58, 65, 62, 68, 67. What i
Brrunno [24]
65 because if you put all the numbers in order and work out which one is in the middle you get the median. i enjoy using the rhyme. Hey diddle diddle, the medians the middle, you add then divide for the mean, the mode is the one that you see the most and the range is the difference between.
8 0
3 years ago
The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili
Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

\lambda= 4.5

Formula:

P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}

a) No accidents occur in one week.

P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111

b) 5 or more accidents occur in a week.

P( x \geq 5) = 1-\displaystyle \sum P(x

c) One accident occurs today.

The mean number of accidents per day is given by

\lambda = \dfrac{4.5}{7} = 0.64

P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747

5 0
2 years ago
Geoff earns $9.25 per hour before taxes, and he works 40 hours per week. Geoff's employer withholds (takes out) 10.65% of geoff'
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Answer:

a

Step-by-step explanation:

6 0
2 years ago
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