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3 years ago

Please solve. w-(y-x)-1

Mathematics

2 answers:

Aleksandr [31]3 years ago

8 0

Let's simplify step-by-step.

w−(y−x)−1

=w+−y+x+−1

=w+x−y−1

Description:

Since this is a small equation the first step is to simplify the equation at the end your answer will end up as w+x−y−1.

The first step is to simplify the equation step by step and to simplify an equation you can first multiplying the factors and use the exponent rules to remove the parentheses. After that your answer will come as =w+x−y−1. Since this is a small equation you don't need to combine like terms. So

w-(y-x)-1 = w+x−y−1.

Answer: =w+x−y−1

Hope this helps.

Alex73 [517]3 years ago

4 0

Answer:

w + x - y -1 that's how you solve it

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3 years ago

Do you hypotenuse of a triangle is 1 foot more than twice the length of the shorter leg the longer leg is 7 feet longer than the

Lera25 [3.4K]

Answer:

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Longer leg: 15 units

Hypotenuse: 17 units

Step-by-step explanation:

We are given $h=1+2s$ where $h$ is the hypotenuse and $s$ is the length of the shorter leg.

We got this equation from reading that the "hypotenuse of a triangle is 1 foot more than twice the length of the shorter leg". I replaced the "hypotenuse of a triangle" with $h$ , "is" with $=$ , "1 foot more than" with $1+$ and finally "twice the length of the shorter leg" with $2s$ .

We also have "longer leg is 7 feet longer than the shorter leg".

I'm going to replace "longer leg" with $L$ .

I'm going to replace "is" with $=$ .

I'm going to replace "7 feet longer than the shorter leg" with $7+s$ .

So we have the equation $L=7+s$ .

So we have a right triangle since something there is a side being referred to as the hypotenuse. We can use Pythagorean Theorem to find a relation between all these sides.

So by Pythagorean Theorem, we have: $s^2+L^2=h^2$ .