15 divided by 3 = 5 equal groups
lx-1 l ≤ 13
There are 2 solutions:
x-1 ≤ 13
and
x-1 ≥ -13
Solve each one
x-1 ≤ 13
add 1 to both sides of the equation
x-1+1≤ 13+1
x ≤ 14
x-1 ≥ -13
Add 1 to both sides:
x-1+1 ≥-13+1
x ≥ -12
-12 ≤ x ≤ 14
Answer:
50, 60, 80, 100, 30
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
To show triangles ABC and DEF congruent by putting them oneach other, you need the following transformations:
reflect triangle DEF across the x-axis
then move triangle DEF left 1 unit
finally move triangle DEF down 1 unit
the option that has all this is C
Answer:
Step-by-step explanation:
If y=0
6=3(0) -2y
6= -2y
6÷ -2 -2y÷ -2
<u>-3=y</u>
<u />
If x=0
*Same steps*
6=3x - 2(0)
6/3=3x/3
<u>x=2</u>
