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Lynna [10]
3 years ago
13

Solve for x. Round to the nearest tenth

Mathematics
1 answer:
alina1380 [7]3 years ago
8 0

Answer:

x = 50.3

Step-by-step explanation:

Sin(x) = \frac{opp}{hyp} =  \frac{30}{39}

solve for x, if you're using a calculator, make sure it's in degrees mode

sin^{-1} (x) = (30/39)

about 50.3

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What are the roots to<br> the equation<br> 2x² + 6x-1=0?
lys-0071 [83]

Answer:

The roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}    

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = \frac{ - b}{a}

And products of roots = \frac{c}{a}

So, m + n = \frac{ - 6}{2} = - 3

And m × n =  \frac{ - 1}{2}

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 (\frac{ - 1}{2})

Or, (m - n)² = 9 + 2 = 11

I.e m - n = \sqrt{11}

Again m + n = - 3    And m - n = \sqrt{11}

Solving this two equation

(m + n) + ( m - n) = - 3 + \sqrt{11}

I.e 2 m =  - 3 + \sqrt{11}

Or, m = \frac{-3}{2} + \frac{\sqrt{11} }{2}

Similarly n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      

Hence the roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      Answer

6 0
4 years ago
Help asap! Please! Much appreciated!
stiv31 [10]
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Answer:

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Step-by-step explanation:

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What's -96= -6 (8 - k)
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Divide both sides with -6 to then get 16=8-k. Then subtract 8 to both sides. to get 8=-k. Finally, divide both sides by -1 to get your answer, -8=k.
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Ilia_Sergeevich [38]
C - remember the vertical line test determines if something is a function. A function has 1 x value for 1 y value. A B and D have more than one y value for a given x value.
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