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lara [203]
3 years ago
8

What is the point-slope equation of a line with slope -5 that contains the point (6, 3)

Mathematics
1 answer:
mafiozo [28]3 years ago
7 0

Answer:

\large\boxed{B.\ y-3=-5(x-6)}

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

We have the slope m = -5 and the point (6, 3). Substitute:

y-3=-5(x-6)

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Answer:

(y + 5) = -7(x + 3)

Step-by-step explanation:

Point Slope Form:  (y - y1) = m(x - x1)

<u>Step 1:  Find Slope</u>

m = \frac{y2 - y1}{x2 - x1}

m = \frac{-19 - (-5)}{-1 - (-3)}

m = \frac{-19 + 5}{-1 + 3}

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<u>Step 2:  Put into point slope form</u>

Point Slope Form:  (y - y1) = m(x - x1)

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