Question

What is the point-slope equation of a line with slope -5 that contains the point (6, 3)

Answer 1

Answer:

$\large\boxed{B.\ y-3=-5(x-6)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point

We have the slope m = -5 and the point (6, 3). Substitute:

$y-3=-5(x-6)$