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dmitriy555 [2]
3 years ago
5

Two opponents Playing chess start out with 32 pieces on the chess board . Each person loses an equal amount of pieces over 15 mi

nutes . By this time , only 20 piece remain . How many pieces did each person lose ?
Mathematics
1 answer:
QveST [7]3 years ago
5 0

Answer:

Each individual lost 6 pieces

Step-by-step explanation:

Initially, there were 32 pieces

After a while, 20 was left

The number of pieces lost will be 32-20 = 12 pieces

We are told that equal number of pieces were lost

So the number of pieces lost per individual will be:

12/2 = 6 pieces

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Diano4ka-milaya [45]

Answer: c

Step-by-step explanation:

If the population triples every three hours, you would multiply three by the number of one hour to the power of three, making three hours. This function would triple it every three hours.

4 0
3 years ago
Find the m∠SAQ.<br><br><br> 44°<br><br><br> 46°<br><br><br> 57°<br><br><br> 77°
dimulka [17.4K]

Answer:

X=57

Step-by-step explanation:

77+46+X=180

123+X=180

X=180-123

X=57

7 0
3 years ago
Read 2 more answers
THe product of three numbers is 3150. Two of the number are 14 and 15. Find the third number
Sholpan [36]

Answer:

15

Step-by-step explanation:

Let's call the mystery number x.

14\cdot 15\cdot x=3150 \\\\210x=3150 \\\\x=3150/210=15

Hope this helps!

4 0
4 years ago
Read 2 more answers
Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,
MrRissso [65]

Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

n-1=51

Therefore, the probability of drawing a three at the 2nd draw is

p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784

Then, at the third draw, the previous 2 cards are not replaced, so there are now

n-2=50

cards in the deck. So, the probability of drawing a jack is

p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08

Therefore, the total probability of drawing an ace, a three and then a jack is:

p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}

4 0
3 years ago
A band has 36 members. They are arranged into 6 equal rows. How many band members are in each row? Can the same 36 members be pl
Galina-37 [17]

Answer:

6 people would be in each row // It isn't possible for there to be 7 equal rows

Step-by-step explanation:

36 members/6 rows= 6 people per row // 36 members/7 rows= 5.14..... people per row (just doesn't work!)

6 0
4 years ago
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