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kolezko [41]
3 years ago
7

Help me please :(*****​

Mathematics
2 answers:
DiKsa [7]3 years ago
7 0

Answer:

54

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o-na [289]3 years ago
5 0

Answer:

Step-by-step explanation:

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Calculate the area of each circle and show work
Shtirlitz [24]

Answer:

area = 2.54 {ft}^{2}

Step-by-step explanation:

The formula to find the area of a circle is

area \: of \: circle \:  = \pi {r}^{2}

Let pi be (3.14), the radios as given in the question is (0.9). Therefore;

\pi {r}^{2}  =  \\ (3.14) \: {(0.9)}^{2}  \\ 3.14 \times 0.81 =  \\ 2.5434 \: or \: 2.54 {ft}^{2}

7 0
2 years ago
Read 2 more answers
Given that sin(x)= 7/11, find cos(90-x)
marta [7]
Yes indeed it is 7/11
6 0
3 years ago
Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.
vesna_86 [32]

Factorize the denominator:

\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}

If x\neq\pm2, we can cancel the factors of x^2-4, which makes x=-2 and x=2 removable discontinuities that appear as holes in the plot of g(x).

We're then left with

\dfrac1{x+1}

which is undefined when x=-1, so this is the site of a vertical asymptote.

As x gets arbitrarily large in magnitude, we find

\displaystyle\lim_{x\to-\infty}g(x)=\lim_{x\to+\infty}g(x)=0

since the degree of the denominator (3) is greater than the degree of the numerator (2). So y=0 is a horizontal asymptote.

Intercepts occur where g(x)=0 (x-intercepts) and the value of g(x) when x=0 (y-intercept). There are no x-intercepts because \dfrac1{x+1} is never 0. On the other hand,

g(0)=\dfrac{0-4}{0+0-0-4}=1

so there is one y-intercept at (0, 1).

The domain of g(x) is the set of values that x can take on for which g(x) exists. We've already shown that x can't be -2, 2, or -1, so the domain is the set

\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}

8 0
3 years ago
Suppose a 50-foot ladder is leaning against a wall. Which statements about the base of the ladder are true?
Liula [17]

Answer and Step-by-step explanation:

These are the statements that make the question complete:

A. If the base is 24 feet from the wall, the ladder reaches 45 feet up the wall.

B. If the base is 30 feet from the wall, the ladder reaches 40 feet up the wall.

C. If the base is 27 feet from the wall, the ladder reaches 44 feet up the wall.

D. If the base is 14 feet from the wall, the ladder reaches 48 feet up the wall.

Since the ladder leans against a wall, a right angle triangle is formed. Since the ladder is now slant, then it's length becomes the hypothenuse.

The correct statements can be gotten through Pythagoras theorem which says:

A² + B² = C² where C is the hypothenuse and A and B are the other two sides.

Since the hypothenuse is 50, we can test each statement by taking the square of the two sides and add them up, if they are equal to 50² = 2500, then the statement is true.

A. 24² + 45² = 576 + 2025 = 2601 ≠ 2500, therefore it is false.

B. 30² + 40² = 900 + 1600 = 2500, therefore it is true.

C. 27² + 44² = 729 + 1936 = 2665 ≠ 2500, therefore it is false

D. 14² + 48² = 196 + 2304 = 2500, therefore it is true.

From here, statements B and D are true while the rest are all false.

7 0
3 years ago
One of the legs of a right triangle measures 12 cm and the other leg measures 13 cm find the measure of the hypotenuse if necess
Amanda [17]

Answer:

17.7 cm

Step-by-step explanation:

One of the legs of a right triangle measures 12 cm and the other leg measures 13 cm find the measure of the hypotenuse if necessary round the nearest 10th

To find the Hypotenuse of a right angle triangle, we solve using Pythagoras Theorem

Hypotenuse ² = Opposite ² + Adjacent ²

Hypotenuse = √Opposite ² + Adjacent ²

Opposite = 12 cm

Adjacent = 13 cm

Hence,

Hypotenuse = √12² + 13²

= √144 + 169

= 17.691806013 cm

Approximately = 17.7 cm

Therefore, the measure of the Hypotenuse is 17.7 cm

6 0
3 years ago
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