Question

The product of two consecutive square numbers is 144. Work out the two numbers

Answer 1

Answer:

9 and 16

Step-by-step explanation:

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Answer 2

Let the first number be = x

Let the second number which is consecutive be = x+1

As given, the product of two consecutive square numbers is 144

$x^{2}*(x+1)^{2}=144$

Square rooting both sides we get

$x(x+1)=12$

$x^{2}+x=12$

$x^{2}+x-12=0$

$x(x+4)-3(x+4)=0$

$(x-3)(x+4)=0$

$x=3$ or $x=-4$

Neglect the negative value so we get x=3

Hence, one number is 3 and the consecutive number is = 3+1=4

The square of the numbers are 9 and 16.