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3 years ago

10

How do you solve an equation vertically??!!??

2 answers:

wel3 years ago

7 0

By solving it in your head

Serggg [28]3 years ago

6 0

Answer:

You have to give us a question to answer vertically if you want us to show u how to answer vertically

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Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

4 0

3 years ago

1/3·(−3x+4y−5z) help plz

Maksim231197 [3]

Answer:

To solve this we need to form 2 equations with only 2 variables.

x+4y-5z=-7

2x+y+5z=8

3x+5y=1

15x+10y+15z=35

6x+3y+15z=24

9x+7y=11

Now we need to use these to find x and y

9x+15y=3

9x+7y=11

8y=-8

y=-1

Therefore:

x=2

From this we can find that:

2(2)-1+5z=8

Therefore z=1

The answer is x=2, y=-1, z=1

7 0

3 years ago

Read 2 more answers

Is y = 3(x - 2) linear or nonlinear

mixas84 [53]

Answer:

The equation is Linear

Step-by-step explanation:

6 0

2 years ago

Help me please don’t need an explanation just a quick answer

Vikki [24]

Cfxgxhcgxjcbchcjchxjfhx

5 0

3 years ago

Please help me!! Thank you

mrs_skeptik [129]

Answer:

The area of the circle is 153.86. Plz give me brainliest!

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers