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Over [174]
3 years ago
13

Answer these two questions Please

Mathematics
1 answer:
alekssr [168]3 years ago
7 0

Answer:

2.

a) likely

b) unlikely

c) equally likely to occur or not occur

d) certain

e) unlikely

3.

In order of least to most likely to occur

A C B D

P(A) 0

P(B) 4/9

P(C) 1/9

P(D) 5/9

I hope this was helpful :-)

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x^2-x-12=x^2+3x-4x-12=x(x+3)-4(x+3)=(x+3)(x-4)\\\\x^2-2x-8=x^2+2x-4x-8=x(x+2)-4(x+2)=(x+2)(x-4)\\\\4x^2=2x\cdot2x



\dfrac{x^2-x-12}{2x}:\dfrac{x^2-2x-8}{4x^2}=\dfrac{x^2-x-12}{2x}\cdot\dfrac{4x^2}{x^2-2x-8}\\\\=\dfrac{(x+3)(x-4)}{2x}\cdot\dfrac{2x\cdot2x}{(x+2)(x-4)}=\dfrac{(x+3)}{1}\cdot\dfrac{2x}{(x+2)}\\\\=\boxed{\dfrac{2x^2+6x}{x+2}}

4 0
4 years ago
What is the solution for this system of linear equations?<br> {23x+4=y<br> 4−2x=y
liubo4ka [24]
We can subsitute since
23x+4=y and
4-2x=y
therefor
23x+4=y=4-2x
so
23x+4=4-2x
minus 4 on both sides
23x=-2x
add 2x to both sides
25x=0
divide both sides by... uh oh
I guess x=0

sub
4-2(0)=y
4-0=y
4=y

the solution is (0,4)
3 0
4 years ago
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