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Over [174]
3 years ago
13

Answer these two questions Please

Mathematics
1 answer:
alekssr [168]3 years ago
7 0

Answer:

2.

a) likely

b) unlikely

c) equally likely to occur or not occur

d) certain

e) unlikely

3.

In order of least to most likely to occur

A C B D

P(A) 0

P(B) 4/9

P(C) 1/9

P(D) 5/9

I hope this was helpful :-)

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What is this equation????<br> m=y2-y1\y2-y1​
kakasveta [241]

Answer:

Are you sure it ia not x2 - x1 in the denominator?

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3 years ago
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What is the value of the fourth term in a geometric sequence for which a1 =<br> 30 and r= 1/2
Tcecarenko [31]

Answer:

3¾

Step-by-step explanation:

Geometric sequence also known as geometric progression, can be said to be a sequence with a constant ratio between the terms.

Formula for geometric sequence:

a^n = a ( n-1 ) * r

Given:

First term, a1 = 30

ratio, r = ½

Required:

Find the fourth term

Where, the first term, a¹ = 30

Second term: a² = 30 * ½ = 15

Third term: a³ = 15 * ½ = 7.5

Fourth term: a⁴ = 7.5 * ½ = 3.75 = 3¾

Therfore the fourth term of the geometric sequence is 3¾

6 0
3 years ago
Which of the following is a solution to the equation "y=3x-1"
nalin [4]

we have

y=3x-1

we know that

If the point is an equation solution, it must satisfy the equation.

<u>case a</u>) (4,1)

Substitute the values of x and y in the equation

1=3*4-1

1=12-1

1\neq11 -------> the point is not solution of the equation

<u>case b</u>) (2,5)

Substitute the values of x and y in the equation

5=3*2-1

5=6-1

5=5 -------> the point is solution of the equation

<u>case c</u>) (4,3)

Substitute the values of x and y in the equation

3=3*4-1

3=12-1

3\neq11 -------> the point is not solution of the equation

<u>case d</u>) (0,-3)

Substitute the values of x and y in the equation

-3=3*0-1

-3\neq-1 -------> the point is not solution of the equation

therefore

<u>the answer is</u>

The point (2,5) is solution of the equation


4 0
3 years ago
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A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
Valentin [98]

Answer:

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12.8

The sample deviation calculated s=4.324 \approx 4.3

12.8-4.604\frac{4.324}{\sqrt{5}}=3.896    

12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704    

So on this case the 99% confidence interval would be given by (3.896;21.704)    

Step-by-step explanation:

Data: 10,9,20,13,12

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12.8

The sample deviation calculated s=4.324

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,4)".And we see that t_{\alpha/2}=4.604

Now we have everything in order to replace into formula (1):

12.8-4.604\frac{4.324}{\sqrt{5}}=3.896    

12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704    

So on this case the 99% confidence interval would be given by (3.896;21.704)    

6 0
3 years ago
Which function is shown on the graph?
LenaWriter [7]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
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