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Over [174]
3 years ago
13

Answer these two questions Please

Mathematics
1 answer:
alekssr [168]3 years ago
7 0

Answer:

2.

a) likely

b) unlikely

c) equally likely to occur or not occur

d) certain

e) unlikely

3.

In order of least to most likely to occur

A C B D

P(A) 0

P(B) 4/9

P(C) 1/9

P(D) 5/9

I hope this was helpful :-)

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The figure in the picture is made up of 5 congruent squares. If the perimeter of the entire figure is 21.6 cm, find its area.
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Perimeter is length plus width so use that to help you
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you and a friend go out to dinner. The cost of the meal is $45.22. The sales tax is 5% and deliver 16% tip. what is the total co
kumpel [21]

Answer: $57.72

Step-by-step explanation:

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Evaluate. <br> 3+2⋅6<br> _____<br> 3
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The answer is 5. Hope that helps :)
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Read 2 more answers
If a monopolist supplies goods at a price; P = 170 - Q, with marginal cost; MC = 52. Find the quantity and price
Arada [10]

Answer:

Quantity = 59 units

Price = $111

Step-by-step explanation:

The Demand function is given by

P = 170 - Q

The Marginal cost is given by

MC = 52

We are asked to find the quantity and price of goods.

Firstly, obtain the Marginal revenue function from the demand function

The Total revenue is given by

TR = P \times Q \\\\TR = (170 - Q) \times Q \\\\TR = 170Q - Q^2

The Marginal revenue is the derivative of the Total revenue,

MR = \frac{d}{dQ} (TR) = 170Q - Q^2 \\\\MR = \frac{d}{dQ} (TR) = 170 - 2Q \\\\

Assuming that the monopolist maximizes profits,

MR = MC \\\\170 - 2Q = 52\\\\2Q = 170 - 52\\\\2Q = 118\\\\Q = 118/2\\\\Q = 59

Therefore, the quantity is 59 units.

The price of each good is

P = 170 - Q \\\\P = 170 - 59 \\\\P = 111

Therefore, the price is $111.

3 0
3 years ago
Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
Murrr4er [49]

Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

3 0
3 years ago
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