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3 years ago

Answer these two questions Please

Mathematics

1 answer:

alekssr [168]3 years ago

7 0

Answer:

a) likely

b) unlikely

c) equally likely to occur or not occur

d) certain

e) unlikely

In order of least to most likely to occur

A C B D

P(A) 0

P(B) 4/9

P(C) 1/9

P(D) 5/9

I hope this was helpful :-)

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What is this equation???? m=y2-y1\y2-y1

kakasveta [241]

Answer:

Are you sure it ia not x2 - x1 in the denominator?

7 0

3 years ago

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What is the value of the fourth term in a geometric sequence for which a1 = 30 and r= 1/2

Tcecarenko [31]

Answer:

3¾

Step-by-step explanation:

Geometric sequence also known as geometric progression, can be said to be a sequence with a constant ratio between the terms.

Formula for geometric sequence:

$a^n = a ( n-1 ) * r$

Given:

First term, a1 = 30

ratio, r = ½

Required:

Find the fourth term

Where, the first term, a¹ = 30

Second term: a² = 30 * ½ = 15

Third term: a³ = 15 * ½ = 7.5

Fourth term: a⁴ = 7.5 * ½ = 3.75 = 3¾

Therfore the fourth term of the geometric sequence is 3¾

6 0

3 years ago

Which of the following is a solution to the equation "y=3x-1"

nalin [4]

we have

$y=3x-1$

we know that

If the point is an equation solution, it must satisfy the equation.

case a) $(4,1)$

Substitute the values of x and y in the equation

$1=3*4-1$

$1=12-1$

$1\neq11$ -------> the point is not solution of the equation

case b) $(2,5)$

Substitute the values of x and y in the equation

$5=3*2-1$

$5=6-1$

$5=5$ -------> the point is solution of the equation

case c) $(4,3)$

Substitute the values of x and y in the equation

$3=3*4-1$

$3=12-1$

$3\neq11$ -------> the point is not solution of the equation

case d) $(0,-3)$

Substitute the values of x and y in the equation

$-3=3*0-1$

$-3\neq-1$ -------> the point is not solution of the equation

therefore

the answer is

The point $(2,5)$ is solution of the equation

4 0

3 years ago

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A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

Valentin [98]

Answer:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=12.8$

The sample deviation calculated $s=4.324 \approx 4.3$

$12.8-4.604\frac{4.324}{\sqrt{5}}=3.896$

$12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704$

So on this case the 99% confidence interval would be given by (3.896;21.704)

Step-by-step explanation:

Data: 10,9,20,13,12

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=12.8$

The sample deviation calculated $s=4.324$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,4)".And we see that $t_{\alpha/2}=4.604$