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kati45 [8]
3 years ago
9

a cone is a solid made from a disc, a point not in the same plane as the discs and all points between them. true or flase?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

False.

Step-by-step explanation:

A cone is not a solid made from a disc, a point not in the same plane as the discs and all points between them.

Mathematically, the volume of a cone is given by the formula;

V = \frac{1}{3} \pi r^{2}h

Where;

V is the volume of the cone.

r is the radius of the base of the cone.

h is the height of the cone.

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The area of a rectangle is represented by the function A = n^3 - 6n^2 - 8n + 48.
aliya0001 [1]

Answer:

P = 2(n - 6) + 2(n^2 - 8)

Step-by-step explanation:

Remembering that Area = Length times Width, we factor the given function

A = n^3 - 6n^2 - 8n + 48 in the expectation that the resulting factors represent the length and width respectively:

A = n^3 - 6n^2 - 8n + 48 factors as follows:

A = n^2(n - 6) - 8(n - 6), or A = (n - 6)(n^2 - 8)

We can label '(n - 6)' "width" and '(n^2 - 8'

length.

Then the perimeter, P, of the rectangle is P = 2(length) + 2(width). which works out here to:

P = 2(n - 6) + 2(n^2 - 8)

5 0
3 years ago
For each store, what is the ratio of the number of cans to the price?
leva [86]
Well $ 4.50 for the 24 pack.$2.50 for the 4 for 10,12 pack and the last is $3.00.
7 0
3 years ago
Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000
zvonat [6]

Answer:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

A = \int\limits^t_ {1} \,{13\cdot x^{3}}  dx

A = 13 \int\limits^t_1 {x^{3}} \, dx

A = \frac{13}{4}\cdot (t^{4}-1)

Evaluated areas are presented below:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

8 0
4 years ago
5 hundreds x 10 in standard form
Effectus [21]
5 hundreds is 500. So 500x10= 5000. Answer:5000
4 0
3 years ago
Read 2 more answers
Assume that foot lengths of women are normally distributed with a mean of 9.6 in and a standard deviation of 0.5 in.a. Find the
Makovka662 [10]

Answer:

a) 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b) 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c) 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 9.6, \sigma = 0.5.

a. Find the probability that a randomly selected woman has a foot length less than 10.0 in

This probability is the pvalue of Z when X = 10.

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 9.6}{0.5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881.

So there is a 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b. Find the probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

This is the pvalue of Z when X = 10 subtracted by the pvalue of Z when X = 8.

When X = 10, Z has a pvalue of 0.7881.

For X = 8:

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 9.6}{0.5}

Z = -3.2

Z = -3.2 has a pvalue of 0.0007.

So there is a 0.7881 - 0.0007 = 0.7874 = 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c. Find the probability that 25 women have foot lengths with a mean greater than 9.8 in.

Now we have n = 25, s = \frac{0.5}{\sqrt{25}} = 0.1.

This probability is 1 subtracted by the pvalue of Z when X = 9.8. So:

Z = \frac{X - \mu}{s}

Z = \frac{9.8 - 9.6}{0.1}

Z = 2

Z = 2 has a pvalue of 0.9772.

There is a 1-0.9772 = 0.0228 = 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

5 0
3 years ago
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