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3 years ago

PLEASE HELP 100 points to who ever gives me the answer Compare the numbers using >, <, or =.

Mathematics

1 answer:

never [62]3 years ago

7 0

Answer:

a) -2 < 3

b) |-12| < |15| <em>(the absolute value of -12 is 12 so that's comparing 12 to 15)</em>

c) 3 > -4

d) |15| > |-12|

e) 7 > -11

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Listed below are prices in dollars for one night at different hotels in a certain region. Find the range, variance, and standar

hodyreva [135]

Answer:

Step-by-step explanation:

Given is a list of prices in dollars for one night at different hotels in a certain region

To find range, variance and std deviation.

Mean 155.75

Standard Error 23.80782434

Median 150

Mode #N/A

Standard Deviation 67.33869616

Sample Variance 4534.5

Kurtosis -1.593759971

Skewness 0.344624422

Range 172

Minimum 86

Maximum 258

Sum 1246

Count 8

Thus we find range = 172 $. This gives an idea about the lowest and highest difference.

Variance = Average of squares of deviations from the mean= 4533.329 $^2gives us an idea about the dispersion of data. This helps to have an idea about the price rise or low in different hotels

Std deviation is square root of variance 67.33 $ shows an idea about the dispersion and also coefficient of variation as a ratio of mean to std deviation.

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4 years ago

Which phrase represents the algebraic expression ä 0+ ??

Fed [463]

Answer:

the product of one-fourth and a number plus seven. So it's A

Step-by-step explanation:

7 0

3 years ago

What is k in 26-k/13=28

charle [14.2K]

Answer:

k = -338

Step-by-step explanation:

The goal is to isolate k on one side, so let's start by multiplying 13 on both sides to get rid of the demoninator. After we do that, we'll be left with:

26 - k = 28(13)

26 - k = 364

Subtracting 26 from both sides gives us:

-k = 338

Multiplying both sides by -1 to make k positive gives us:

k = -338

Hope this helped! :)

6 0

3 years ago

An 80% increase followed by a 40% decrease

scZoUnD [109]

You start with 100%, add 80% for the increase and you get 180%, take away 40% for the decrease and you get 140%

4 0

3 years ago

The following measurements (in picocuries per liter) were recorded by a set of argon gas detectors installed in a research facil

Reptile [31]

Answer:

The 95% confidence interval for the mean level of argon gas present in the facility is (374.4, 401.7).

Step-by-step explanation:

Before building the confidence interval, we have to find the sample mean and the sample standard deviation.

Sample mean:

$\overline{x} = \frac{381.3+394.8+396.1+380}{4} = 388.05$

Sample standard deviation:

$s = \sqrt{\frac{(381.3-388.05)^2+(394.8-388.05)^2+(396.1-388.05)^2+(380-388.05)^2}{3}} = 8.58$

Confidence interval:

We have the standard deviation for the sample, so the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 3.1824

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 3.1824\frac{8.58}{\sqrt{4}} = 13.65$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 388.05 - 13.65 = 374.4

The upper end of the interval is the sample mean added to M. So it is 388.05 + 13.65 = 401.7

The 95% confidence interval for the mean level of argon gas present in the facility is (374.4, 401.7).

4 0

3 years ago