Ryan throws a baseball upward with an initial velocity of 12 m/s from a height of 2m above the ground. How long will it take for
the baseball to hit the ground? Round answer to the nearest 10th of a second.
1 answer:
Answer:
It will take 2.6 s for the ball to hit the ground.
Step-by-step explanation:
This is a standard physics problem
The equation that defines the movement of Ryans baseball is given by the initial velocity, and the acceleration
Distance = Do + Vo*t + 0.5*a*t^2
Where
Do is the initial distance.
(Do = 2m over the ground)
Vo is the initial velocity = 12m/s
a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 )
t is the time
We substitute in the equation, and solve for t (time)
(0)= 2+ (12)*t + 0.5*(-9.8)*t^2
We get that
t = 2.606 s = 2.6 s
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Answer:
a = -1 , b = 4 , c = 3 , d = 1
Step-by-step explanation:
The general rules of exponent:
===================================================
Given:
The right hand side = (-xy)³ (xz) = (-1)³ x³ y³ x z = (-1) x⁴ y³ z
Comparing the right hand side with the left hand side
∴ a = -1
∴ b = 4
∴ c = 3
∴ d = 1