Solve for x A) 9 B) 11 C) 5 D)-4

Josh sees that the ratio of boys to girls is 1/2, so he says that half of the students are boys?

miss Akunina [59]

Answer:

no.

Step-by-step explanation:

The ratio is 1/2. That means that if there is one boy, there are 2 girls. Altogether, there are 3 people.

The answer is no. Boys would be one-third and girls are two-thirds.

If this helped, please mark me as brainliest. Thank you! ;)

7 0

3 years ago

Can someone please help me with this?

satela [25.4K]

Answer:

Choice C

Step-by-step explanation:

Rational numbers are any number that can be written as a quotient or fraction.

7 0

3 years ago

PLEASE HELP

Blababa [14]

30 mph because the question actually states the answer

8 0

4 years ago

What does part b and c means ?

pshichka [43]

The coefficient closest to zero is B, and the coefficient with the least value is C in the represented graphs.

<h3>What is a graph?</h3>

A graph can be defined as a visual representation or a diagram that represents data or values.

The modulus functions are given in the represented graphs

The modulus function graph has a distinct v-shape. It is equivalent to f (x) = x, except that negative y values are mirrored on the x-axis. This is due to the fact that the modulus of a number x is the same number.

According to the given graph, we can see that when the value of the coefficient closest to zero is B and the coefficient with the least value is C.

Therefore, the coefficient closest to zero is B, and the coefficient with the least value is C.

Learn more about the graphs here:

brainly.com/question/16608196

#SPJ1

7 0

1 year ago

The desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.5. To test whether the true average

Reil [10]

Answer:

a) Null hypothesis : H₀ : μ = 5.5

Alternative Hypothesis : H₁ : μ < 5.5

b) The test statistic

|t| = |-3.33| = 3.33

c) P - value lies between in these intervals

0.001 < P < 0.005

Step-by-step explanation:

Step( i ):-

Given data the Population mean 'μ' = 5.5

The small sample size 'n' = 16

The sample mean (x⁻) = 5.25

Given the percentage of SiO2 in a sample is normally distributed with a sigma of 0.3.

Null hypothesis : H₀ : μ = 5.5

Alternative Hypothesis : H₁ : μ < 5.5

Level of significance ∝ = 0.01

Step(ii):-

The test statistic

$t = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$t = \frac{5.25 -5.5}{\frac{0.3}{\sqrt{16} } }$

On calculation , we get

t = -3.33

|t| = |-3.33| = 3.33

Step(iii):-

P - value

The degrees of freedom γ = n-1 = 16-1 =15

The calculated value t = 3.33 (check t-table) lies between the 0.001 to 0.005

0.001 < P < 0.005

Condition(i)

P - value < ∝ then reject H₀

Condition(ii)

P - value > ∝ then Accept H₀

we observe that 0.001 < P < 0.005

P- value < 0.01

we rejected H₀

(or)

The tabulated value = 2.60 at 0.01 level of significance with '15' degrees of freedom

The calculated value t = 3.33 > 2.60 at 0.01 level of significance with '15' degrees of freedom

The null hypothesis is rejected

Conclusion:-

Accepted Alternative hypothesis H₁

The Claim that the true average is smaller than 5.5

4 0

3 years ago