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3 years ago

15

a hawk soars at an altitude of 1,800ft. if the awk descends to the ground in 45 min, what is its vertical speed?

1 answer:

Verizon [17]3 years ago

4 0

Does it come with any anwsers

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Through which angle of rotation does the image of a regular pentagon coincide with its preimage?

aev [14]

Its 72 degrees i just did this one plato

8 0

3 years ago

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How to write g(x)=2x+3/x+1 in the form of:g(x)=a/x+p +q

aliya0001 [1]

Hello,

Please write correctly.

g(x)= (2x+3)/(x+1) to be written like a/(x+p) + q

It is very simple!

(2x+3)/(x+1)= [(2x+2)+1]/(x+1)= (2(x+1)+1)/(x+1)= 2+1/(x+1)

7 0

3 years ago

Brandon graphed one line in a system of equations. The system has only one solution, (0,3). Which equations could also be part o

AlladinOne [14]

Answer:

y = 3 and y = x + 3

Step-by-step explanation:

The equation y = 3 whose graph is a line parallel to x-axis can be a part of the system.

Consider the equation y = x + 3.

Substitute (0, 3).

3 = 0 + 3

So, (0, 3) lies on y = x + 3 and this can also be a part of the system.

6 0

3 years ago

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Find the slope of the line going through the points (0, -5) and (-2,1)

kvasek [131]

Answer:

$\displaystyle m=-3$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Coordinates (x, y)
Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

<u>Step 1: Define</u>

Point (0, -5)

Point (-2, 1)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>

Substitute in points [Slope Formula]: $\displaystyle m=\frac{-5-1}{0--2}$
[Fraction - Denominator] Simplify: $\displaystyle m=\frac{-5-1}{0+2}$
[Fraction - Numerator] Subtract: $\displaystyle m=\frac{-6}{0+2}$
[Fraction - Denominator] Add: $\displaystyle m=\frac{-6}{2}$
[Fraction] Divide: $\displaystyle m=-3$

8 0

2 years ago

D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

2 years ago