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Ray Of Light [21]
3 years ago
13

The Diaz family bought 7 bags of cookies. Each bag had 14 cookies. They have since eaten 29 of the cookies. How many cookies do

they have left?
Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0

Answer:

They have 69 cookies left.

Step-by-step explanation:

7 x 14 = 98

98 - 29 = 69

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The equation of a graph is 4x - 3y = 5. What is the x-intercept?
user100 [1]
X intercept is where y=0
so make y=0
4x-0=5
x=5/4
4 0
3 years ago
Read 2 more answers
Consider the following game, played with three standard six-sided dice. If the player ends with all three dice showing the same
ddd [48]

Answer:

a

 P(A) =  \frac{1}{36}

b

P(B) = \frac{15}{36}

c

P(U) = \frac{11}{36}

Step-by-step explanation:

From the question we are told that

   The  number of dice is  n  =  3

Generally  for all three dice to show the same number the second and the third dice must have the same outcome  as the outcome of the first dice.

This means that the number of outcome the first die can  have is  6  (6 sides), the number of outcome which the second and the third dice can have is  1 (they must match the first )

So the probability that all three dice show the same number on the first roll is mathematically represented as

      P(A) =  \frac{6}{6} * \frac{1}{6} *  \frac{1}{6}

=>   P(A) =  \frac{1}{36}

Generally for two of the three dice show the same number after the first roll then the number of outcome for  one of the  dice would be is  6 , the number of outcome for another one must be   1(i.e it must match the first ) , the number of outcome for the remaining one must be   5 (i.e it can show any of the remaining  5  sides which the first and second dice are not showing )

Now the number of ways of selecting this 2 dice that show the same number from the 3 dice is mathematically represented as

     N  =  ^3C_2

Here C stands for combination

So

      N  =  ^3C_2  = 6

So the probability that exactly two of the three dice show the same number after the first roll is mathematically represented as  

      P(B) = N   \frac{1}{6} *  \frac{5}{6}

=>  P(B) = \frac{15}{36}

Generally from the question we are told that if two dice match, the player re-rolls the die that does not match.

Now the probability that  the die that did not match the first  time will match the second time is

     P(E ) =  \frac{1}{6}

Generally if that one die does not show the same number in the second round , the probability that it will match  in the third round is

    P(R) =  \frac{5}{6} *  \frac{1}{6}

Generally the probability that he wins (i.e when all three are showing the same number ) and  exactly two is showing the same number is mathematically represented as

       P(K) =  P(E)* P(B) + P(R)* P(B)

=>    P(K) =  \frac{1}{6} * \frac{15}{36}  +  \frac{5}{6} *  \frac{1}{6} * \frac{15}{36}

=>  P(K)= \frac{165}{1296}

So the probability that the player wins, conditioned on exactly two of the three dice showing the same number after the first roll is mathematically represented as  

    P(U) =  \frac{\frac{165}{1296}}{\frac{15}{36} }

=>  P(U) = \frac{11}{36}

     

 

6 0
3 years ago
Match the function with the graph.
astraxan [27]
Can I see the graph?
6 0
3 years ago
Read 2 more answers
Sara went out for lunch with a group of 25 friends. Each person purchased either a sandwich for $4.00 or a bowl of soup for $3.5
Brrunno [24]
The answer would be A)12
4 0
3 years ago
Which equation can be used to represent six added to twice the sum of a numbee and four is equal to one half of the difference o
Ronch [10]

Answer:  6 + 2 (x+4) =   \frac{3}{2}(3-x)

Step-by-step explanation:

let the number be x , then :

six added to twice the sum of a number and four means :

6 + 2 (x+4)

one half of the difference of three and the number means :

\frac{3}{2}(3-x)

combining the two , we have

6 + 2 (x+4) = \frac{3}{2}(3-x)

6 0
3 years ago
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