Question

This diagram shows a pre-image △ABC , and its image, ​ △A′′B′′C′′ ​ , after a series of transformations.

Answer 1

First ABC is reflected across the y axis to become A'B'C'

Then A'B'C' is rotated 90 counterclockwise about the origin to make it A"B"C"

Because the transformations are both rigid, the pre-image and image are congruent

Hope this helped

Answer 2

Answer:

Step-by-step explanation:

ΔABC is reflected across y axis [ as we can see points A',B,'C' and A,B,C are equidistant from y - axis. y- axis is working like a mirror ]

ΔA'B'C' is rotated 90 degrees counterclockwise about the origin to become A"B"C". [Sides A'B' and A"B" are perpendicular to each other]

Because the transformations are both rigid [No dilation in the figure A"B"C"], the pre image and the image are congruent [All corresponding sides are equal].