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Bad White [126]
2 years ago
6

Estimate the percentage of 53% of 59

Mathematics
2 answers:
Sedaia [141]2 years ago
8 0
53% of 59 is 31.27 or 31.3
Semmy [17]2 years ago
7 0
It would be around 50
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carla's vacation will cost at least $718. she saves $85 each week. she already has $463. how many weeks,w,does she have to save
aleksklad [387]
She already has 463 that's a set amount she started at an her start amount won't change an she's wanting 718 an she is savin 85 a week so every week she gets more money so that number changes so ur equation is 85W+463=718 then u do a two step equation
4 0
2 years ago
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Please Answer Both Questions
Ymorist [56]

Answer:

a. 42 x 39 = 1638 ft²

b. small = 12(large)

small = 12(48)

= 576

576 - 48 = 528 more small posters

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2 years ago
What are the zeros of the function? f(x)=+-6x
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The function given is a line with one zero at the center (0,0)
7 0
2 years ago
A-4b2 for a = -3 and b = 5
s344n2d4d5 [400]

Answer:

the answer is -43

Step-by-step explanation:

i just looked it up

7 0
3 years ago
Read 2 more answers
Need the answers plz
Shkiper50 [21]
1)
           x^2 + 4x - 5
y =   --------------------
              3x^2 - 12

Vertcial asym => find the x-values for which the equation is not defined and check whether the limit goes to + or - infinite

=> 3x^2 - 12 = 0 => 3x^2 = 12

=> x^2 = 12 / 3 = 4

=> x = +/-2

Limit of y when x -> 2(+) = ( 2^2 + 4(2) - 5) / 0 = - 1 / 0(+) =  ∞

Limit of y when x -> 2(-) = - 1 / (0(-) = - ∞

Limit of y when x -> - 2(+) = +∞

Limit of y when x -> - 2(-) = -

=> x = 2 and x = - 2 are a vertical asymptotes

Horizontal asymptote => find whether y tends to a constant value when x -> infinite of negative infinite

Limi of y when x -> - ∞ = 1/3

Lim of y when x -> +∞ = 1/3

=> Horizontal asymptote y = 1/3

x - intercept => y = 0

=>
          x^2 + 4x - 5
0 =   ------------------ => x ^2 + 4x  - 5 = 0
              3x^2 - 12

Factor x^2 + 4x - 5 => (x + 5) (x - 1) = 0 => x = - 5 and x = 1

=> x-intercepts x = - 5 and x = 1

Domain: all the real values except x = 2 and x = - 2

2)  y = - 2 / (x - 4) - 1

using the same criteria you get:

Vertical asymptote: x = 4

Horizontal asymptote: y = - 1

Domain:all the real values except x = 4

Range: all the real values except y = - 1

3) 

x/ (x + 2) + 7 / (x - 5) = 14 / (x^2 - 3x - 10)

factor x^2 - 3x - 10 => (x - 5)(x + 2)

Multiply both sides by (x - 5) (x + 2)

=> x(x - 5) + 7( x + 2) = 14

=> x^2 - 5x + 7x + 14 = 14

=> x^2 + 2x = 0

=> x(x + 2) = 0 => x = 0 and x = - 2 but the function is not defined for x = - 2 so it is not a solution => x = 0

Answer: x = 0
4 0
3 years ago
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