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aleksandr82 [10.1K]
3 years ago
10

Pls help me with this problem

Mathematics
1 answer:
Alchen [17]3 years ago
6 0

Answer:

Angle A: 90

Angle B: 48

Angle C: 42

Side length A (Hypotinuse): 23.9

SIde length B (Opposite): 17.8

Side length C (Adjacent): 16

Step-by-step explanation:

https://www.calculator.net/triangle-calculator.html?vc=42&vx=&vy=&va=90&vz=16&vb=&angleunits=d&x=0&y=0

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If a=i+7j+k and b=i+11j+k, find a unit vector with positive first coordinate orthogonal to both a and
Scilla [17]
Take the cross product, then normalize the result.

\mathbf a\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\1&7&1\\1&11&1\end{vmatrix}=-4\,\mathbf i+4\,\mathbf k

This has norm

\|\mathbf a\times\mathbf b\|=\sqrt{(-4)^2+4^2}=4\sqrt2

and so a unit vector orthogonal to both given vectors is

\dfrac{\mathbf a\times\mathbf b}{\|\mathbf a\times\mathbf b\|}=-\dfrac1{\sqrt2}\,\mathbf i+\dfrac1{\sqrt2}\,\mathbf k

An equally correct answer would be the negative of this vector, since \mathbf b\times\mathbf a=-\mathbf a\times\mathbf b.
5 0
3 years ago
Law of cosines.Anyone good in Trigonometry?​
marin [14]

Answer:

c=11.8\ units

Step-by-step explanation:

we know that

The formula of law of cosines is equal to

c^2=a^2+b^2-2(a)(b)cos(C)

where

a, b and c are sides. C is the angle opposite side c

In this problem we have

a=3\ units\\b=10\ units

C=120^o

substitute the given values

c^2=3^2+10^2-2(3)(10)cos(120^o)

c^2=109-(60)cos(120^o)

c^2=109-(60)(-0.5))

c^2=109+30

c^2=139

c=11.8\ units

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3 years ago
Damian is going to invest in an account paying an interest rate of 5.2% compounded
viktelen [127]

Answer:

650

Step-by-step explanation:

651.606881968=P

round: 650

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Which of the following algebraic equations is equivalent to ?
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If it's mutiple choice can I see the options :) would make this easier

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3 years ago
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