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3 years ago

Will mark Brainliest!!!

Mathematics

1 answer:

KiRa [710]3 years ago

5 0

Answer:

6 and 10

Step-by-step explanation:

Let a = the first number(3/5 of the second number namely b)

Let b = the number that is 5/3 of a

a=3/5 b

Assuming they are both positive integers, obviously you will have to add 4 to a.

4+a = b

4 + 3/5 b = b

2/5 b = 4

b = 10

a=6

ONLY ASSUMING IF THEY ARE BOTH POSITIVE INTEGERS

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Peggy wants to run 5 miles in less than 60 minutes. What inequality shows what her rate should be ?

sleet_krkn [62]

The inequality that her rate should be is
<span>5 > 60</span>

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3 years ago

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Solve the system of linear equations and show your work.<br> −8x+5y=26<br> 9x−3y=−3

maks197457 [2]

X is 7 and y is 2 I am pretty sure

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3 years ago

Answer the question right or I report you

zubka84 [21]

Answer:

3 ÷ 0.25

Step-by-step explanation:

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3 years ago

A truck has a force of 2000 newtons and is moving 10 miles per hour. How much mass does the truck have?

worty [1.4K]

Answer:

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F=m×a

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2 years ago

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Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20

vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of $y=f(x)$ is a vertical has an asymptote at $x=a$ if at least one of the following statements is true:

$1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty$

The function is:

$f(x)=\frac{x^2+7x+10}{x^2+9x+20}$

First of all, let't factor out:

$f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq 5$

From here:

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty$

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty$

Accordingly:

$x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}$

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

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3 years ago