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Anarel [89]
3 years ago
14

Can someone help please?

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
4 0

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A company earns a profit of $100 the first month it is in business. Every month after that, the company earns a profit that is 1
Inga [223]
11/2 of $100 is $550
($550 x 4) + $100 = <span>$2,300
hope this helps</span>
3 0
4 years ago
Find the x-coordinates of the points where the graph crosses the x-axis.<br> y = (x - 3)(x + 8)
sleet_krkn [62]

Answer:

The x-coordinates of the points are x = 3 and x = - 8.

Step-by-step explanation:

We have to find the x-coordinates of the points where the graph of equation y = (x - 3)(x + 8) crosses the x-axis.

Now, the x-intercept of a function implies that y = 0 {Because on x-axis, y-value is zero}

Hence, (x - 3)(x + 8) = 0

⇒ (x - 3) = 0 and (x + 8) = 0

⇒ x = 3 and x = - 8

Therefore, the x-coordinates of the points are x = 3 and x = - 8. (Answer)

6 0
3 years ago
The area of a circular field is 154msqu. What is the perimeter of the field?(pi=22/7) 44 49 88 176
OLga [1]

Answer:

44m

Step-by-step explanation:

A = \pir² = 154

   = 22/7 * r² = 154

   = r²  = 154 * 7/22

   = r²  = 49

   = r = √49

   = r = 7m

Perimeter of circle = 2\pir

                               = 2 * 22/7 * 7

                               = 44/7 * 7

                               = <u>44 m</u>

<u></u>

Hope it helps

Mark it as Brainliest

     

7 0
3 years ago
Read 2 more answers
Please Help!!!
Hoochie [10]
By synthetic division,

-5  |  1    -6    -42    79
.    |        -5     55   -65
- - - - - - - - - - - - - - - - - 
.    |  1   -11    13    14

\implies\dfrac{x^3-6x^2-42x+79}{x+5}=x^2-11x+13+\dfrac{14}{x+5}
\implies x^3-6x^2-42x+79=(x^2-11x+13)(x+5)+14

When x=-5, you're left with a remainder of 14.
5 0
4 years ago
34. I need to know how to write the equation in slope-intercept form and graph it. My biggest question is how to write it in slo
vagabundo [1.1K]
Maybe it’s y=1x-2. I hope this helps since we have no clue what the x is in the question we just assume it’s own
8 0
3 years ago
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