Answer: OPTION C.
Step-by-step explanation:
By definition:
![a^{1/n}=\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%7B1%2Fn%7D%3D%5Csqrt%5Bn%5D%7Ba%7D)
You must descompose the numbers 160 and 243 into their prime factor:


Simplify the expression, then you obtain the following result:
![\sqrt[5]{2^{5}*5*3^{5}}=2*3\sqrt[5]{5}=6\sqrt[5]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E%7B5%7D%2A5%2A3%5E%7B5%7D%7D%3D2%2A3%5Csqrt%5B5%5D%7B5%7D%3D6%5Csqrt%5B5%5D%7B5%7D)
The answer is the option C.
Answer:
This a circle centered at the point
, and of radius "3" as it is shown in the attached image.
Step-by-step explanation:
Recall that the standard formula for a circle of radius "R", and centered at the point
is given by:

Therefore, in our case, by looking at the standard equation they give us, we extract the following info:
1)
since the radius must be a positive number and (
) is not a viable answer.
2)
for (
) to equal 
3)
for (
) to equal 
Therefore, we are in the presence of a circle centered at the point
, and of radius "3". That is what we draw as seen in the attached image.
The answer is a, you add the numbers up get 4.22 which is equivalent to 4 whole aka ones and since .22 is a decimal you use your tenths and hundredths