The ratio of life expectancy to gestation period is greatest at point (A) A.
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What is life expectancy?</h3>
- Life expectancy is a statistical measure of how long an organism is expected to live based on its birth year, current age, and other demographic factors such as gender.
- The most commonly used metric is life expectancy at birth (LEB), which has two definitions.
To find the labeled points, which represent the animal for which the ratio of life expectancy to gestation period is greatest:
- The graph below shows life expectancy on the y-axis and gestation period on the x-axis.
- The life expectancy to gestation period ratio for point A is 7/22.5 = 14/45.
- For point B, the ratio is 8/45.
- Because the y coordinate is greater at Y than at X, which has the same x coordinate, we only consider the ratio at D, which is 10/51.
- Since 14/45 > 8/45, we only have to compare 14/45 and 10/51.
- So, 14 × 51 = 714 and 45 × 10 = 450.
- Then, 14/45 > 10/51.
Therefore, the ratio of life expectancy to gestation period is greatest at point (A) A.
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The correct question is given below:
Of the labeled points, which represent the animal for which the ratio of life expectancy to gestation period is greatest?
A) A
B) B
C) C
D) D
Answer:
38.9
Step-by-step explanation:
Answer:
C.
Step-by-step explanation:
If f(c)=0 then (c,0) is on the graph.
In general, if f(a)=b then (a,b) is on the graph.
By factor theorem if f(c)=0 then x-c is a factor.
If x-c is a factor then x-c will divide f(x) evenly. We know this because the remainder will be 0 because we know x-c is a factor of f.
The only choice that I have said in this whole thing that is true is C.
Answer:
B. 3.5
Step-by-step explanation:
I believe this is correct :')
Answer:
Step-by-step explanation:
Find AOS
X = -b/2a
X = -65/2(-14)
X = -65/-28
X = 2.32 secs
t = 2.32secs
A) y value when t = 2.32 is the maximum height.
Substitute t in the equation.
h(t)= -14t^2+65t+1.75
h(t)= (-14 * 2.32²) + (65 * 2.32) + 1.75
= (-14 * 5.38 ) + (65 * 2.32) + 1.75
= -75.35 + 150.8 + 1.75
= 77.2 ft
Maximum height attained by the ball = 77.2 ft
B) Time the maximum height achieved = 2.32secs
C) The ball off of the ground when it was shot is well t = 0
Substitute t in equation
h(t)= -14t^2+65t+1.75
h(0)= (-14 * 0²) + (65 * 0) + 1.75
= 0 + 0 + 1.75ft
The ball is 1.75ft off the ground when it was shot.