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3 years ago

12

Show work for brainliest.

1 answer:

Svetradugi [14.3K]3 years ago

5 0

Answer:

Equation of the parabola: 12y−72=(x−4)212y−72=(x−4)2 or y=x212−2x3+223y=x212−2x3+223.

Vertex form: y=(x−4)212+6y=(x−4)212+6.

No intercept form.

Vertex: (4,6)(4,6).

Focus: (4,9)(4,9).

Eccentricity: 11.

Directrix: y=3y=3.

Latus rectum: y=9y=9.

The length of the latus rectum: 1212.

Axis of symmetry:

Step-by-step explanation:

from parabola calculator-eMathHelp

I hope it helps.

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Answer:

Asanji drove for $5$ hours before Huong caught up

Step-by-step explanation:

Let the time for which Asanji drove alone is "X" hours

Asanji and Huong met after three hours of driving of Huong.

Total time for which Asanji drove $= X+3$ hours

Thus, distance travelled by Asanji in $X+3$ hours is equal to distance travelled by Huong in $3$ hours

$45 ( X+3) = 75 (3)\\$

On solving the above equation, we get -

$45 X + (45 *3) = 75 *3\\45 X = (75-45)*3\\45 X = 30 *3 \\X = \frac{30 *3}{45} \\X = 2$

Asanji drove for $3 + 2 = 5$ hours before Huong caught up

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3 years ago

point a is at (1 5) and point c is at (-5 -7) find the coordinates of point b on ab such that ac is 6 times as long as ab

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Answer:

b=(0,3)

Step-by-step explanation:

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3 years ago

What are the solutions for the given equation ?⬇️<br><br> x^2- 6x + 12 = 0

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3 years ago

A building's rafter forms the hypotenuse of a 30°-60°-90° triangle with the roof's frame. If the rafter measures 9 feet, then th

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2 years ago

The gate of a stadium ha two pillars each of height 10ft.with four visible lateral faces and 3ft*3ft bases .the top of eaxh pill

lbvjy [14]

The pillars and the pyramids in the stadium gate means that we have to calculate the area of the items that make up the gate one after the other. At the end of the calculation, the calculated areas are then added up.

The total cost of painting is Rs.21344

First, we calculate the area of 1 side of 1 pillar using:

$A = Height * Base$

Where

$Height = 10ft$ --- Height of the pillar

$Base = 3ft$ --- Base of the pillar

So:

$A = 10ft * 3ft$

$A = 30ft^2$

The area of the 4 sides of the pillar is:

$A_2 = 4 * A$ --- i.e. 4 multiplied by the area of 1 side

$A_2 = 4 * 30ft^2$

$A_2 = 120ft^2$

The area of the 2 pillars is:

$Area_1 = 2 * A_2$ --- i.e. 2 multiplied by the area if 1

$Area_1 = 2 * 120ft^2$

$Area_1 = 240ft^2$

Because one part of the pyramid won't be visible, we calculate the area of the pyramid using:

$Area = lw + l\sqrt{(w/2)^2 + h^2} + w\sqrt{(l/2)^2 + h^2}$

Where:

$h = 2$ -- the height

$l = w = 3$ --- the base of the pillar is the length and width of the pyramid.

So, we have:

$Area = 3\sqrt{(2/2)^2 + 2^2} + 3\sqrt{(2/2)^2 + 2^2}$

$Area = 3\sqrt{1 + 4} + 3\sqrt{1 + 4}$

$Area = 3\sqrt{5} + 3\sqrt{5}$

$Area = 6\sqrt{5}$

For the two pyramids, the area is:

$Area_2 = 2 * 6\sqrt 5$ -- 2 multiplied by area of 1

$Area_2 = 12\sqrt 5$

$Area_2 = 26.8$

So, the total area to be painted is:

$Total = Area_1 + Area_2$ --- the sum of the area of the pillars and the pyramids

$Total = 240+26.8$

$Total = 266.8ft^2$

The unit cost of paint is:

Rate = Rs80 per sq.ft

The total cost of painting is:

$Cost = 80 * 266.8$

$Cost = Rs.21344$

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3 years ago