1. The Crusaders have won 11 games and lost 9 games this season. What percent of its games

Why do you switch the inequality sign when multiplying or dividing by a negative?

Andreas93 [3]

If we multiply or divide both sides of an inequality by a negative number, you have to flip the inequality. Hope this helps :)

5 0

3 years ago

Given that A=27, B=43 and c=17, solve triangle ABC to the nearest hundredth

katrin2010 [14]

When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] / 1,462
cos (A) = 1,409 / 1,462
cos (A) = 0.96374829001368
Angle A = 15.475

Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
sin(B) = sin(15.475) * 43 / 27
sin(B) = 0.26682 * 43 / 27
sin (B) = 0.424935555555
Angle B = 25.147 Degrees
Remember the arc sine (0.424935555555) also equals 154.85

Finally, calculating the third angle is quite easy
Angle C = 180 - Angle (A) - Angle(B)
Angle C = 180 - 15.475 - 154.85
Angle C = 9.675

Source:
http://www.1728.org/trigtut2.htm

6 0

3 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0

3 years ago

PLEASE HELP LOL what type of angles are <4 and <8

Phantasy [73]

Answer:

C. Corresponding angles

Step-by-step explanation:

Visualize the two points of intersection and the four angles around each of them being separated. If you put the on top of each other, you can see that angle 4 corresponds with angle 8.

4 0

3 years ago

Read 2 more answers

-6 - 3(2x + 4) = 18what’s the answer

Brrunno [24]

Answer:

$x=-6$