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Tanya [424]
3 years ago
10

Find the area of the parallelogram Height=4cm Base=5cm

Mathematics
2 answers:
4vir4ik [10]3 years ago
5 0

Answer:

The area of the parallelogram is 20cm²

Elenna [48]3 years ago
4 0

Answer:

A = 20 cm²

Step-by-step explanation:

The area (A) of a parallelogram is calculated as

A = bh ( b is the base and h the height ) , then

A = 5 × 4 = 20 cm²

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The volume is 300 cubic centimeters for a triangular prism.
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3 years ago
HELP PLEASE<br><br> Find the measure of the <br> missing angles.
user100 [1]

Step-by-step explanation:

value of d = 90° ( as it's a perpendicular)

e = 49° ( vertically opposite angle)

as, sum of all angles on a straight line is 180°

so,

48° + f = 180°

f = 180 - 49 = 131°

f = 131°

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8 0
3 years ago
Read 2 more answers
When two or more plane shapes from another shape the shape formed is called​
Ira Lisetskai [31]

Answer:

solid shapes

Step-by-step explanation:

solid shapes are formed from two or more plane shapes

5 0
3 years ago
Read 2 more answers
I need help with questions #7 and #8 plz
katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

c^2 = a^2 + b^2 - 2ab \cos C

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

18^2 = 12^2 + 16^2 - 2(12)(16) \cos C

324 = 144 + 256 - 384 \cos C

-384 \cos C = -76

\cos C = 0.2

C = \cos^{-1} 0.2

C = 78.6^\circ

Now we use the law of sines to find angle A.

Law of Sines

\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}

We know c and C. We can solve for a.

\dfrac{a}{\sin A} = \dfrac{c}{\sin C}

\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}

Cross multiply.

18 \sin A = 12 \sin 78.6^\circ

\sin A = \dfrac{12 \sin 78.6^\circ}{18}

\sin A = 0.6535

A = \sin^{-1} 0.6535

A = 40.8^\circ

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

a^2 = b^2 + c^2 - 2bc \cos A

b^2 = a^2 + c^2 - 2ac \cos B

c^2 = a^2 + b^2 - 2ab \cos C

Find angle A:

a^2 = b^2 + c^2 - 2bc \cos A

8^2 = 18^2 + 12^2 - 2(18)(12) \cos A

64 = 468 - 432 \cos A

\cos A = 0.9352

A = 20.7^\circ

Find angle B:

b^2 = a^2 + c^2 - 2ac \cos B

18^2 = 8^2 + 12^2 - 2(8)(12) \cos B

324 = 208 - 192 \cos A

\cos B = -0.6042

B = 127.2^\circ

Find angle C:

c^2 = a^2 + b^2 - 2ab \cos C

12^2 = 8^2 + 18^2 - 2(8)(18) \cos B

144 = 388 - 288 \cos A

\cos C = 0.8472

C = 32.1^\circ

8 0
3 years ago
An equailateral triangle is also an
Alinara [238K]

Answer:

C) isosceles triangle

Step-by-step explanation:

equilateral triangle has all sides the same and all angles the same

180/3 = 60  so each angle is 60 degrees

A) obtuse triangle

means it has an angle bigger than 90 degrees

B) right triangle

that means it has an angle at 90 degrees

C) isosceles triangle

That means it has 2 sides that are the same

D) scalene triangle​

that means it has no sides the same

If it has 3 sides the same. it must have 2 sides the same. So any equilateral triangle must be an isosceles triangle

4 0
3 years ago
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