Question

Is (0,0) a solution to this system?

Answer 1

Answer:

A. Solution to $y \ge x^2 - 4$ but not to $y < 2x - 1$

Step-by-step explanation:

Given

$y \ge x^2 - 4$

$y < 2x - 1$

Required

Is $(0,0)$ a solution?

$(0,0)$ implies that:

$x = 0\ and\ y = 0$

To check if it is a solution or not, we simply substitute 0 for x and for y in the given inequalities

$y \ge x^2 - 4$ becomes

$0 \ge 0^2 - 4$

$0 \ge 0- 4$

$0 \ge - 4$

This solution is true

$y < 2x - 1$ becomes

$0 < 2 * 0 - 1$

$0 < 0 - 1$

$0 < - 1$

This solution is not true because 0 is greater than 1.

Hence, option (A) is correct