First, i put the equation in y=mx+b by dividing 2, since its 2y. since it’s perpendicular we’re talking about you switch the sides (opposite reciprocals). the rest should be self explanatory.
Right square pyramid V=189cm³
Answer:
a) "ascend"
Step-by-step explanation:
a)
The equation is 
This question is asking for the value of the directional derivative in the direction of -j [since south that's y negative]
So, this is the negative of partial derivative of y. Thus we have:

Now we are at (100,120,1106), we take y value of 120 and put it in the partial:

We take the negative, that is -(-2.4) = 2.4
Since this is positive, we can say the hill is sloping upward at this point, so you will start to ascend.
Use a calculator go step by step