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ad-work [718]
3 years ago
12

The six part of the age that I will have in 4 years

Mathematics
1 answer:
Ahat [919]3 years ago
5 0

Answer:

10 i think i didnt really get your question though

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Please find attached photograph for your answer.

8 0
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Write an inequality for the following statement : "you have to be at least 18 years old to vote. "
Svetllana [295]
Thats not the case in other countries, just the us
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There are 50 books side by side on a library bookshelf. Each book is two inches thick. How far is it from the first page of book
sveticcg [70]

Answer:

100inches

Step-by-step explanation:

50books

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3 0
3 years ago
[SCREENSHOT INCLUDED] If f(x) = sqrt(2x+1) then f '(4) =
Sphinxa [80]

Using the definition,

f'(4) = \displaystyle \lim_{x\to4} \frac{f(x)-f(4)}{x-4}

The numerator in the difference quotient is

f(x) - f(4) = \sqrt{2x+1} - \sqrt{2\cdot4+1} = \sqrt{2x+1}-3

Multiply the numerator and denominator by the conjugate of this expression,

\displaystyle \frac{\sqrt{2x+1}-3}{x-4} \cdot \dfrac{\sqrt{2x+1}+3}{\sqrt{2x+1}+3}

The modified numerator reduces to a difference of squares,

\displaystyle \frac{\left(\sqrt{2x+1}\right)^2-3^2}{(x-4)\left(\sqrt{2x+1}+3\right)}

Simplify this to get

\displaystyle \frac{2x+1-9}{(x-4)\left(\sqrt{2x+1}+3\right)} = \frac{2(x-4)}{(x-4)\left(\sqrt{2x+1}+3\right)}

Since x is approaching 4, it never actually takes on the value of 4, so (x - 4)/(x - 4) reduces to 1. Then the limit is equivalent to

f'(4) = \displaystyle \lim_{x\to4} \frac{f(x)-f(4)}{x-4} = \lim_{x\to4}\frac2{\sqrt{2x+1}+3}

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f'(4) = \dfrac2{\sqrt{2\cdot4+1}+3} = \dfrac26 = \boxed{\dfrac13}

6 0
2 years ago
What are the solutions of the equation x^4-9x^2+8=0? Use u substitution to solve
krok68 [10]
Exact Form:
x
=
2
√
2
,
−
2
√
2
,
−
1
,
1
x
=
2
2
,
-
2
2
,
-
1
,
1
Decimal Form:
x
=
2.82842712
…
,
−
2.82842712
…
,
−
1
,
1
7 0
3 years ago
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