#1
Clear shown in graph
#2
No
At. no where graph passes through origin so y intercept is not 0 at anywhere
#3
Domain is x values
#4
Range is y values set
Answer:
The equation of the quadratic function shown is;
x^2+ 2x -3
Step-by-step explanation:
Here in this question, we need to know the quadratic equation whose graph was shown.
The key to answering this lies in knowing the roots of the equation.
The roots of the equation are the solution to the quadratic equation and can be seen from the graph at the point where the quadratic equation crosses the x-axis.
The graph crosses the x-axis at two points.
These are at the points x = -3 and x = 1
So what we have are;
x + 3 and x -1
Multiplying both will give us the quadratic equation we are looking for.
(x + 3)(x-1) = x(x -1) + 3(x-1)
= x^2 -x + 3x -3 = x^2 + 2x -3
Answer:
6 dollars per hour
Step-by-step explanation:
We can set up and solve an equation to answer this question. For this problem, let x stand for the amount he earned per hour. The equation that represents this situation is 3.2x + 4.3x = 45. The first term represents monday and the second represents tuesday. When these add up they should equal 45 because that is the total amount he made. To find his pay per hour, solve for x.
First, combine the like terms
Next, divide both sides by 7.5
162.15 is the answer because you have to multiply 0.15•141 then add 21.15 to the 141 :)
ANSWER
the factor <em>will </em>
<em>1</em><em>1</em><em> </em><em>is </em><em>common</em><em> </em><em>in </em><em>both </em><em>the </em><em>given </em><em>term</em>
<em>so,</em><em> </em><em>when </em><em>we </em><em>take </em><em>1</em><em>1</em><em> </em><em>from </em><em>both </em><em>term </em>
<em>it </em><em>will </em><em>left </em><em>with </em><em> </em>
<em>1</em><em>1</em><em>(</em><em> </em><em>2</em><em>+</em><em>1</em><em>)</em><em> </em>
<em>this </em><em>is </em><em>the </em><em>final </em><em>answer</em><em> </em>
<em>hope </em><em>it </em><em>helps </em><em>and </em><em>u </em><em>have </em><em>a </em><em>great</em><em> </em><em><u>day</u></em>